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In the following exercises, solve the system of equations by using substitution.

x2+4y2=42x-y=1

Short Answer

Expert verified

Solution:x=1617,y=1517x=0,y=-1

Step by step solution

01

Given Information 

Two equations are

x2+4y2=42x-y=1

02

Identify the graph and check the possible solution 

The graph of two equations

Both the graph intersects at

(0,-1) and (0.941, 0.882)

03

Solve the second equation for y 

2x-y=12x-1=yy=2x-1

Substitute it in first equation and solve for x

x2+42x-12=417x2-16x+4=417x2-16x=0x(17x-16)=0x=017x-16=017x=16x=1617

04

Solve for y

Substitute the x value and find out y

y=2x-1x=0y=2(0)-1y=-1x=1617y=21617-1y=1517

Solution is

(0,-1)1617,1517

05

Check the solution

Substitute each ordered pair and verify the solution

(0,-1)2x-y=12(0)-(-1)=1,Truex2+4y2=4(0)2+4(-1)2=4,True1617,15172x-y=12(1617)-(1517)=1,Truex2+4y2=4(1617)2+4(1517)2=4,True

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