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In the following exercises, using factorial notation, write the first five terms of the sequence whose general term is given.

an=n!n+2!

Short Answer

Expert verified

The first five terms of the sequence are 16,112,120,130,and 142.

Step by step solution

01

Step 1. Given information.

The given general term is,

an=n!n+2!

02

Step 2. Finding the first five terms.

Now, to find the first five terms of the sequence we will substitute 1,2,3,4,and 5respectively in the general term then we get,

an=n!n+2!
an=n!n+2!
an=n!n+2!
an=n!n+2!
an=n!n+2!
a1=13!
a2=2!4!
a3=3!5!
a4=4!6!
a5=5!7!
a1=13.2.1
localid="1668005252784" role="math" a2=2·14·3·2·1
localid="1668005262205" role="math" a3=3·2·15·4·3·2·1
localid="1668005273995" role="math" a4=4·3·2·16·5·4·3·2·1
localid="1668005246335" role="math" a5=5·4·3·2·17·6·5·4·3·2·1
a1=16
a2=112
a3=120
a4=130
a5=142

Therefore, the first five terms of the sequence are localid="1645342057494" 16,112,120,130,and 142.

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