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In the following exercise, solve the system of equations by using elimination.

2x2+y2=11x2+3y2=28

Short Answer

Expert verified

1,3,1,-3,-1,3,-1,-3

Step by step solution

01

Step 1. Given information. 

In this case, the following system of equations are given:

2x2+y2=11x2+3y2=28

02

Step 2. Solution by elimination. 

Since both the equations are in the standard form, to eliminate x2, multiply both sides of the second equation by 2 and then subtract from the first equation:

2x2+y2-2x2-6y2=11-56-5y2=-45y2=-45-5=9y=9y=3

Substitute the values of yin the first equation:

When y=3:

2x2+32=112x2=11-9x2=1x=1

When y=-3:

2x2+-32=112x2=11-9x2=1x=1

Expressing the solutions as ordered pairs:

1,3,1,-3,-1,3,-1,-3

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