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Chapter 11: Q. 11.32TI (page 1095)

Graph x=2(y-3)2+2using properties.

Short Answer

Expert verified

The graph is

Step by step solution

01

Given information

Given the equationx=2(y-3)2+2

02

Identify the constants a, h, k and the other parameters

Comparing, we get

x=2(y-3)2+2a=2(h,k)=(2,3)

As a=2, parabola opens to the right

03

Calculate the x intercept

Calculating, we get

x=2(y-3)2+2x=2(0-3)2+2x=20

04

Calculate the y intercept

Calculating, we get

x=2(y-3)2+22(y-3)2+2=02(y-3)2=-2(y-3)2=-1

Square can't be negative so there are no yintercept

The symmetrical point is(20,6)

05

Sketching the graph

The graph is

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