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Solve. Where appropriate, include approximations to three decimal places. If no solution exists, state this. $$ \ln (x+5)+\ln (x+1)=\ln 12 $$

Short Answer

Expert verified
The solution is \(x = 1\).

Step by step solution

01

- Combine Logarithmic Expressions

Use the property of logarithms \(\text{ln}(a) + \text{ln}(b) = \text{ln}(a \times b)\) to combine the left-hand side: \(\text{ln}((x+5)(x+1)) = \text{ln}(12)\).
02

- Exponential Elimination

Since the logarithmic function is one-to-one, we can remove the natural logarithms from both sides of the equation: \((x+5)(x+1) = 12\).
03

- Simplify the Equation

Expand and simplify the equation: \((x+5)(x+1) = x^2 + 6x + 5 = 12\).
04

- Rearrange to Form a Quadratic Equation

Move all terms to one side of the equation: \((x^2 + 6x + 5) - 12 = 0\), which simplifies to \(x^2 + 6x - 7 = 0\).
05

- Solve the Quadratic Equation

Factor the quadratic equation: \(x^2 + 6x - 7 = (x + 7)(x - 1) = 0\). This gives the solutions \(x = -7\) and \(x = 1\).
06

- Verify Solutions

Check both solutions in the original logarithmic equation. \(x = -7\) leads to \ln(-2) + \ln(-6)\, which is not valid as the argument of \text{ln}\ must be positive. Thus, only \(x = 1\) is valid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Logarithms
When solving logarithmic equations, it's essential to understand the properties of logarithms. One key property is the 'product rule': \[ \text{ln}(a) + \text{ln}(b) = \text{ln}(a \times b) \].
This property allows us to combine logarithmic expressions into a single logarithm.
In the given equation, this rule helps us merge: \[ \text{ln}(x+5) + \text{ln}(x+1) \] into \[ \text{ln}((x+5)(x+1)) \]
Understanding and applying these properties simplifies complex logarithmic equations, making them easier to solve.
Quadratic Equations
Quadratic equations are essential in algebra. They typically appear in the form \[ ax^2 + bx + c = 0 \].
Solving quadratics can be done by factoring, using the quadratic formula, or completing the square.
In the combined equation \[ (x+5)(x+1)=12 \], simplifying leads to a quadratic form: \[ x^2 + 6x + 5 = 12 \], which rearranges to \[ x^2 + 6x - 7 = 0 \].
This is solved by factoring into \[ (x + 7)(x - 1) = 0 \], giving solutions \[ x = -7 \] and \[ x = 1 \].
Exponential Functions
Exponential functions involve expressions where the variable appears as an exponent, such as \[ f(x) = a^x \].
These functions grow very quickly and are the inverse of logarithmic functions.
When solving logarithmic equations, sometimes we use the fact that the logarithm of a number is the exponent to which another fixed number, the base, must be raised to produce that number.
In this exercise, using the property of logarithms, we transformed \[ \text{ln}((x+5)(x+1)) = \text{ln}(12) \] into \[ (x+5)(x+1) = 12 \], effectively removing the logarithms to simplify the equation.
Logarithmic Functions
Logarithmic functions are the inverse of exponential functions and are written as \[ y = \text{log}_b(x) \] where 'b' is the base.
The natural logarithm \[ \text{ln}(x) \] is a special logarithm with the base 'e' (approximately 2.718).
Solving logarithmic equations often involves using properties of logarithms to combine or break down logarithmic expressions.
For example, in studying equations like \[ \text{ln}(x+5) + \text{ln}(x+1) = \text{ln}(12) \], understanding logarithmic properties allows us to simplify and find solutions efficiently.
Always validate the solutions, ensuring the arguments of the logarithms are positive, since logarithms of non-positive numbers are undefined.

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