Chapter 8: Problem 21
Graph the function, label the vertex, and draw the axis of symmetry. $$ g(x)=-(x-2)^{2} $$
Short Answer
Expert verified
The vertex is (2, 0), and the axis of symmetry is x = 2. The parabola opens downwards.
Step by step solution
01
Identify the Vertex
The function given is in the form of a vertex form of a quadratic function: \( g(x) = -(x-2)^{2} \). In this form \( g(x) = a(x-h)^2 + k \), the vertex \( (h, k) \) can be identified. Here, \( a = -1 \), \( h = 2 \), and \( k = 0 \). Thus, the vertex is \( (2, 0) \).
02
Draw the Axis of Symmetry
The axis of symmetry for a parabola in vertex form \( g(x) = a(x-h)^2 + k \) is the vertical line that passes through the vertex. This line is defined by \( x = h \). Therefore, for the given function, the axis of symmetry is \( x = 2 \). Draw a dashed vertical line at \( x = 2 \) on the graph.
03
Determine the Direction of the Parabola Opening
Because the coefficient \( a \) is negative (\( a = -1 \)), the parabola opens downwards. This means that the vertex is the highest point on the graph.
04
Plot Additional Points
To ensure a more accurate graph, plot additional points by choosing different \( x \) values. For example, if \( x = 0 \): \( g(0) = -(0-2)^2 = -4 \). If \( x = 1 \): \( g(1) = -(1-2)^2 = -1 \). Plot these points \( (0, -4) \), and \( (1, -1) \) and their symmetric points about the axis of symmetry, \( (4, -4) \) and \( (3, -1) \), respectively.
05
Sketch the Graph
Connect the vertex \( (2, 0) \) and the additional points with a smooth, U-shaped curve that opens downwards, ensuring it is symmetric with respect to the axis of symmetry \( x = 2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
vertex form
The vertex form of a quadratic function provides an easy way to identify the vertex and other properties of the parabola. The general format is \( g(x) = a(x-h)^2 + k \). Here,
- \( a \) determines the direction and width of the parabola
- \( h \) and \( k \) represent the vertex coordinates
- \( a = -1 \), indicating the parabola opens downwards
- \( h = 2 \), which is the x-coordinate of the vertex
- \( k = 0 \), which is the y-coordinate of the vertex
axis of symmetry
The axis of symmetry is a vertical line that divides the parabola into two mirror-image halves. In vertex form, \( g(x) = a(x-h)^2 + k \), the axis of symmetry is given by the equation \( x = h \). This means it passes directly through the vertex. For \( g(x) = -(x-2)^2 \), the axis of symmetry is \( x = 2 \). This can be visualized as a dashed vertical line at \( x = 2 \), showing where the parabola will have its symmetrical behavior. Knowing where this line is helps when plotting additional points, because for any point \( (x_1, y) \) on one side, there is a corresponding point \( (x_2, y) \) with \( x_2 \) such that \( x_1 eq x_2 \) but both are equidistant from \( x = h \). This ensures the graph is accurate and well-balanced.
parabola
A parabola is a u-shaped graph that can open either upwards or downwards depending on the value of \( a \) in the quadratic function. If \( a \) is positive, the parabola opens upwards, and if \( a \) is negative, it opens downwards. For instance, in \( g(x) = -(x-2)^2 \), \( a = -1 \), so the parabola opens downwards. The vertex represents the highest point (if the parabola opens down) or the lowest point (if it opens up). To graph a parabola accurately, it's helpful to plot the vertex and axis of symmetry first, then use additional points to shape the curve. For example, choosing x-values and calculating corresponding y-values:
- If \( x = 0 \): \( g(0) = -(0-2)^2 = -4 \)
- If \( x = 1 \): \( g(1) = -(1-2)^2 = -1 \)