Chapter 5: Problem 45
Squares of Binomials Multiply. $$(2 y-7)^{2}$$
Short Answer
Expert verified
4y^2 - 28y + 49
Step by step solution
01
Write Down the Formula for Squaring a Binomial
To square a binomial, use the formula \( (a-b)^2 = a^2 - 2ab + b^2 \).
02
Identify the Terms in the Binomial
In the binomial \( (2y - 7) \), identify \( a \) and \( b \). Here, \( a = 2y \) and \( b = 7 \).
03
Square the First Term
Square the first term, \( a \): \[ (2y)^2 = 4y^2 \].
04
Multiply the Terms by 2 and Together
Multiply the first term and the second term by 2: \[ 2 \times 2y \times 7 = 28y \]. This gives the middle term but with a negative sign, since the original expression is \( (2y - 7) \): \[ -28y \].
05
Square the Second Term
Square the second term, \[ b \]: \[ 7^2 = 49 \].
06
Combine the Results
Combine the results obtained from the previous steps: \[ 4y^2 - 28y + 49 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Expansion
Binomial expansion is a method used in algebra to expand expressions that are raised to a power, typically involving two terms. This can be applied to tasks such as squaring a binomial, which is exactly what we've seen in this exercise. Instead of manually multiplying the binomial with itself, we use a handy formula.
For example: \((a - b)^2 = a^2 - 2ab + b^2\)
The formula saves time and reduces errors, breaking the problem into smaller, manageable steps. Each part of the expanded form represents a distinct operation:
For example: \((a - b)^2 = a^2 - 2ab + b^2\)
The formula saves time and reduces errors, breaking the problem into smaller, manageable steps. Each part of the expanded form represents a distinct operation:
- Squaring the first term (\(a^2\)).
- Multiplying both terms together and doubling the result (\(2ab\)).
- Squaring the second term (\(b^2\)).
Algebraic Multiplication
Algebraic multiplication involves the methodical step-by-step multiplying of terms within expressions. When squaring a binomial, this skill is put to use in several ways:
To expand \((2y - 7)^2\) efficiently, we broke it down as follows:
Begin by calculating \(2 \times 2y \times 7 = 28y\), and since the binomial involves subtraction, this term becomes \(-28y\).
The final combination of all terms leads to the result \(4y^2 - 28y + 49\). This breakdown showcases the importance of correctly multiplying each term and compiling these products to get a precise result.
To expand \((2y - 7)^2\) efficiently, we broke it down as follows:
- First, identify the terms (2y and 7).
- Next, apply the squaring formula.
- Square each term individually: \((2y)^2\) results in \(4y^2\) and \(7^2\) results in 49.
Begin by calculating \(2 \times 2y \times 7 = 28y\), and since the binomial involves subtraction, this term becomes \(-28y\).
The final combination of all terms leads to the result \(4y^2 - 28y + 49\). This breakdown showcases the importance of correctly multiplying each term and compiling these products to get a precise result.
Polynomial Expressions
Polynomial expressions are algebraic expressions that consist of variables and coefficients, constructed using operations of addition, subtraction, multiplication, and non-negative integer exponents. They can take many forms, including the binomials we've been discussing.
In the given problem, our polynomial was initially a binomial raised to a power: \((2y - 7)^2\). Squaring this binomial transformed it into a more complex polynomial: \(4y^2 - 28y + 49\).
Key characteristics to note about polynomial expressions:
In the given problem, our polynomial was initially a binomial raised to a power: \((2y - 7)^2\). Squaring this binomial transformed it into a more complex polynomial: \(4y^2 - 28y + 49\).
Key characteristics to note about polynomial expressions:
- Terms: These are the individual parts that make up the polynomial, such as \(4y^2\), \(-28y\), and 49 in our example.
- Coefficients: These are the numerical parts of the terms (4, -28, and 49).
- Variables: These are symbols like \(y\) that represent numbers.
- Degree: The highest power of the variable in the polynomial. Here, the degree is 2 since \(4y^2\) is the term with the highest exponent.