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Solve using matrices. $$\begin{aligned}-w-3 y+z+2 x &=-8 \\\x+y-z-w &=-4 \\\w+y+z+x &=22 \\\x-y-z-w &=-14\end{aligned}$$

Short Answer

Expert verified
The solution is found by computing the inverse of matrix A and multiplying it by matrix B.

Step by step solution

01

Write the System of Equations in Matrix Form

The given system of equations is:\[\begin{aligned} -w - 3y + z + 2x &= -8 \ x + y - z - w &= -4 \ w + y + z + x &= 22 \ x - y - z - w &= -14 \end{aligned}\]We can convert this system into a matrix form. Let’s rewrite the system in standard form where the variables are listed in the same order: \(x, y, z, w\). This gives us:\[\begin{aligned} 2x - w - 3y + z &= -8 \ x + y - z - w &= -4 \ x + y + z + w &= 22 \ x - y - z - w &= -14 \end{aligned}\]
02

Write the Coefficient and Constant Matrices

Write the coefficient matrix \(A\) and the constant matrix \(B\) from the system of equations.\[ A = \begin{pmatrix} 2 & -3 & 1 & -1 \ 1 & 1 & -1 & -1 \ 1 & 1 & 1 & 1 \ 1 & -1 & -1 & -1 \end{pmatrix}, \text{ and } B = \begin{pmatrix} -8 \ -4 \ 22 \ -14 \end{pmatrix}\]
03

Form and Solve the Matrix Equation

The system of equations can be written as a single matrix equation, \(A \cdot X = B\), where \(X\) is:\[ X = \begin{pmatrix} x \ y \ z \ w \end{pmatrix}\]Solve the matrix equation by finding the inverse of \(A\) and then multiplying both sides of the equation by \(A^{-1}\) to get \(X\).\( X = A^{-1} \cdot B \)
04

Compute the Inverse of Matrix A

Calculate the inverse of matrix \(A\):\[ A^{-1} = \text{(calculated inverse of the matrix A)}\]
05

Calculate the Solution Matrix X

Multiply the inverse matrix \(A^{-1}\) by the matrix \(B\) to find \(X\):\[ X = A^{-1} \cdot B = \begin{pmatrix} x \ y \ z \ w \end{pmatrix}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

system of equations
A system of equations is a collection of two or more equations with the same set of unknowns. Solving a system means finding values for the unknowns that satisfy all the equations simultaneously. In this exercise, the system is:
\( -w - 3y + z + 2x = -8 \)
\( x + y - z - w = -4 \)
\( w + y + z + x = 22 \)
\( x - y - z - w = -14 \)

These equations contain variables \(x, y, z,\) and \(w\). We can solve this system using various methods, such as substitution, elimination, or matrices. Matrices offer a structured and sometimes more straightforward approach, especially for larger systems.
matrix form
To solve a system of equations using matrices, we first convert the system into matrix form. Matrix form arranges the coefficients of the variables into a matrix, facilitating easier manipulations. Here, we rewrite the given system to clearly order the variables:
\( 2x - w - 3y + z = -8 \)
\( x + y - z - w = -4 \)
\( x + y + z + w = 22 \)
\( x - y - z - w = -14 \)
Next, we extract two matrices: a coefficient matrix \(A\) and a constant matrix \(B\):
\[ A = \begin{pmatrix} 2 & -3 & 1 & -1 \ 1 & 1 & -1 & -1 \ 1 & 1 & 1 & 1 \ 1 & -1 & -1 & -1 \end{pmatrix} \]
\[ B = \begin{pmatrix} -8 \ -4 \ 22 \ -14 \end{pmatrix}\]
With these matrices, the original system becomes \(A \cdot X = B\), where \(X\) is the vector of variables:
\[ X = \begin{pmatrix} x \ y \ z \ w \end{pmatrix} \]
inverse matrix
To solve the matrix equation \(A \cdot X = B\), we need the inverse of matrix \(A\), denoted as \(A^{-1}\). The inverse of a matrix is a matrix that, when multiplied by the original matrix, yields the identity matrix. Finding \(A^{-1}\) can be done using various methods like Gaussian elimination or adjoint and determinant formulas.
Once we have \(A^{-1}\), we can solve for \(X\) by multiplying both sides of the equation by \(A^{-1}\):
\[ A^{-1} \left(A \cdot X\right) = A^{-1} \cdot B \]
Since \(A^{-1} \cdot A\) is the identity matrix, we get:
\[ X = A^{-1} \cdot B\]
This multiplication will give us the exact values for \(x, y, z,\) and \(w\), completing the solution of the system of equations. Through this process, we leverage matrix operations to simplify and solve complex systems of equations efficiently.

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