Chapter 9: Problem 37
Graph each of the functions. $$f(x)=3(x-2)^{3}-1$$
Short Answer
Expert verified
The function is a vertically stretched, shifted right by 2, and shifted down by 1 transformed cubic graph.
Step by step solution
01
Understand the Basic Function
The function given is a cubic function of the form \( f(x) = 3(x-2)^3 - 1 \). The basic cubic function is \( g(x) = x^3 \), which we will transform to graph \( f(x) \).
02
Apply Horizontal Shift
The \( (x-2) \) inside the cubic term means we will shift the graph of \( g(x) = x^3 \) horizontally to the right by 2 units. To visualize this, consider how each point \( (x, y) \) on \( g(x) = x^3 \) moves to \( (x+2, y) \) on the horizontally shifted version \( g(x-2) = (x-2)^3 \).
03
Apply Vertical Stretch
The coefficient 3 applies a vertical stretch to the transformed function. This means for every point \( (x, y) \) on \( (x-2)^3 \), the new \( y \)-value will be \( 3y \). This stretches the graph vertically by a factor of 3.
04
Apply Vertical Shift
Subtracting 1 from the entire function, \( 3(x-2)^3 - 1 \), shifts the graph vertically downward by 1 unit. After the stretch and horizontal shift, each point's \( y \)-value is decreased by 1.
05
Confirm Transformations on Key Points
Take a few key points on the original \( g(x) = x^3 \) graph, such as \( (-1, -1), (0, 0), (1, 1) \), transform them by first shifting by +2 (\( (1, 1), (2, 0), (3, 1) \)), then vertical stretch by 3 (\( (1, 3), (2, 0), (3, 3) \)), and finally shift them down by 1 (\( (1, 2), (2, -1), (3, 2) \)) for points on \( f(x) = 3(x-2)^3 - 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cubic Function Transformation
When graphing cubic functions like \( f(x) = 3(x-2)^3 - 1 \), understanding transformations is crucial. The basic cubic function is \( g(x) = x^3 \). This function is characterized by its smooth curve and symmetry about the origin. However, in the given function \( f(x) \), several transformations have been applied.
- **Horizontal Shift:** The expression \( (x-2) \) indicates a shift of the graph of \( g(x) = x^3 \) to the right by 2 units.
- **Vertical Stretch:** The coefficient \( 3 \) multiplies the function, stretching it vertically.
- **Vertical Shift:** The subtraction of 1 moves the entire graph down by 1 unit.
Vertical Stretch and Shift
The concept of vertical stretch and shift is key when you transform a function like \( f(x) = 3(x-2)^3 - 1 \). A vertical stretch is caused by the coefficient \( 3 \). This means that the values of \( y \) on the graph are 3 times their original height from the \( x \)-axis.Consider that each point \( (x, y) \) on the graph of \( g(x-2) = (x-2)^3 \) becomes \( (x, 3y) \). This change means the graph appears narrower because the stretches increase the \( y \)-value for every point.After stretching, the vertical shift comes into play. Subtracting 1 from the function indicates that every point on the previously stretched graph shifts down by 1 unit. For example, if you consider a point \( (x, 3y) \), it transforms into \( (x, 3y - 1) \). This shift downward adjusts the graph, moving the curve vertically along the \( y \)-axis.
Horizontal Shift in Graphing
Horizontal shifts are a fundamental principle in function transformations, especially with cubic functions. In \( f(x) = 3(x-2)^3 - 1 \), you see a classic horizontal shift.The term \( (x-2) \) nestled inside the cubic power causes this shift. Specifically, it moves the baseline graph of \( g(x) = x^3 \) to the right by 2 units.To visualize this, picture each key point \( (x, y) \) on the standard cubic graph as moving rightward by 2 units on every \( x \)-coordinate. For instance, a point originally at \( (0, 0) \) becomes \( (2, 0) \), and similarly, \( (-1, -1) \) becomes \( (1, -1) \). This step makes the whole graph shift along the \( x \)-axis without any alteration in the \( y \)-values initially.