Chapter 9: Problem 30
Specify the domain for each of the functions. $$f(s)=\sqrt{s-2}+5$$
Short Answer
Expert verified
The domain of \( f(s) = \sqrt{s-2} + 5 \) is \([2, \infty)\).
Step by step solution
01
Identify restrictions from the square root
The square root function is only defined for non-negative numbers. This means that the expression inside the square root must be greater than or equal to zero. For the function \( f(s) = \sqrt{s - 2} + 5 \), the expression inside the square root is \( s - 2 \). Therefore, we need \( s - 2 \geq 0 \).
02
Solve the inequality
To find the values of \( s \) for which the inequality \( s - 2 \geq 0 \) holds true, solve for \( s \): \( s - 2 \geq 0 \) implies \( s \geq 2 \).
03
State the domain
The domain of a function is the set of all possible input values. For the function \( f(s) = \sqrt{s - 2} + 5 \), the domain is all values of \( s \) where \( s \geq 2 \). In interval notation, this is expressed as \([2, \, \infty)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square Root Function
The square root function is a crucial mathematical operation often encountered in algebra. It is represented by the symbol \( \sqrt{} \), indicating the principal square root of a number or expression. The principal aspect means we take the non-negative root, as every positive number technically has two square roots (one positive and one negative).
When you see a function involving a square root, such as \( f(s) = \sqrt{s - 2} + 5 \), it's important to remember a key property: the expression inside the square root must be greater than or equal to zero for the function to be defined. This is because you cannot take the square root of a negative number in standard real numbers. Therefore, any function involving a square root must consider this limitation.
When you see a function involving a square root, such as \( f(s) = \sqrt{s - 2} + 5 \), it's important to remember a key property: the expression inside the square root must be greater than or equal to zero for the function to be defined. This is because you cannot take the square root of a negative number in standard real numbers. Therefore, any function involving a square root must consider this limitation.
- If \( s = 2 \), then \( \sqrt{s-2} = \sqrt{0} = 0 \).
- For any \( s > 2 \), \( s-2 \) is a positive number, and the square root is a real number.
- For \( s < 2 \), the expression inside the square root becomes negative, and in standard practices, the function is undefined.
Inequality Solving
Solving inequalities is akin to solving equations, but with a few more things to watch out for. In the case of the function \( f(s) = \sqrt{s - 2} + 5 \), to ensure the square root is defined, you need to solve the inequality \( s - 2 \geq 0 \).
This process involves determining what values of \( s \) satisfy the inequality. Simply rearrange the inequality to solve for \( s \):
This process involves determining what values of \( s \) satisfy the inequality. Simply rearrange the inequality to solve for \( s \):
- We start with the inequality \( s - 2 \geq 0 \).
- By adding 2 to both sides, you get \( s \geq 2 \).
Interval Notation
Interval notation is a concise way of expressing sets of numbers between specified lower and upper bounds. It is particularly useful when describing the domain of a function. For example, in the function \( f(s) = \sqrt{s - 2} + 5 \), we determined that the valid domain based on our inequality solution is \( s \geq 2 \).
Interval notation is used to express this domain as \([2, \, \infty)\), which is interpreted as follows:
Interval notation is used to express this domain as \([2, \, \infty)\), which is interpreted as follows:
- The square bracket \([\) indicates that 2 is included in the interval (closed interval), meaning \( s \) can be exactly 2.
- The parenthesis \()\) after infinity shows that infinity is not a precise number and is not included (open interval).