/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Contains the point \((1,3)\) and... [FREE SOLUTION] | 91Ó°ÊÓ

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Contains the point \((1,3)\) and is parallel to the line \(x+5 y=9\)

Short Answer

Expert verified
The equation of the line is \(x + 5y = 16\).

Step by step solution

01

Identify the Slope of the Given Line

The original line is given by the equation \(x + 5y = 9\). First, we need to identify its slope. We do this by rearranging the equation into the slope-intercept form, \(y = mx + b\). Begin by subtracting \(x\) from both sides: \(5y = -x + 9\). Divide each term by 5: \(y = -\frac{1}{5}x + \frac{9}{5}\). Thus, the slope \(m\) of the line is \(-\frac{1}{5}\).
02

Use Parallel Line Property

Lines that are parallel share the same slope. Thus, any line parallel to the original line will also have a slope of \(-\frac{1}{5}\). Therefore, the slope of our new line is \(m = -\frac{1}{5}\).
03

Substitute the Slope and Given Point into the Point-Slope Formula

To find the equation of the line, use the point-slope form \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is the point \((1, 3)\) and \(m\) is the slope \(-\frac{1}{5}\). Substitute in the values: \(y - 3 = -\frac{1}{5}(x - 1)\).
04

Simplify the Equation

To simplify \(y - 3 = -\frac{1}{5}(x - 1)\), first distribute the slope: \(y - 3 = -\frac{1}{5}x + \frac{1}{5}\). Then add 3 to both sides: \(y = -\frac{1}{5}x + \frac{1}{5} + 3\). Convert 3 to a fraction with a denominator of 5 to facilitate addition: \(y = -\frac{1}{5}x + \frac{1}{5} + \frac{15}{5}\), which simplifies to \(y = -\frac{1}{5}x + \frac{16}{5}\).
05

Conclusion: Write the Equation in Standard Form

To convert the equation to standard form, which is \(Ax + By = C\), first eliminate the fraction by multiplying all terms by 5: \(5y = -x + 16\). Rearrange to get \(x + 5y = 16\). The equation of the line is \(x + 5y = 16\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
The slope-intercept form is a popular way to express the equation of a straight line. This form is written as \( y = mx + b \), where \( m \) is the slope of the line and \( b \) is the y-intercept. The y-intercept is the point where the line crosses the y-axis. This form is particularly useful because it makes it easy to see the slope and intercept directly from the equation.
To convert an equation to the slope-intercept form, you need to solve for \( y \). For example, given the equation \( x + 5y = 9 \), we can rearrange it by isolating \( y \):
  • Subtract \( x \) from both sides to get \( 5y = -x + 9 \).
  • Then, divide each term by 5: \( y = -\frac{1}{5}x + \frac{9}{5} \).
This transformed equation now clearly shows the slope \( m = -\frac{1}{5} \) and the y-intercept \( b = \frac{9}{5} \). This makes it easier to graph the line or compare it with other lines.
Point-Slope Form
Another useful way to express the equation of a line is through the point-slope form. This form is especially handy when you know a point on the line and the slope. It is written as \( y - y_1 = m(x - x_1) \), where \( m \) is the slope, and \( (x_1, y_1) \) are the coordinates of the given point on the line.
In our exercise, we were given a point \((1,3)\) and knew the slope was \(-\frac{1}{5}\). Using point-slope form, we substitute these values in:
  • Start with \( y - 3 = -\frac{1}{5}(x - 1) \).
  • To simplify, distribute the slope: \( y - 3 = -\frac{1}{5}x + \frac{1}{5} \).
  • Finally, solve for \( y \) by adding 3 to both sides: \( y = -\frac{1}{5}x + \frac{1}{5} + 3 \).
  • Convert 3 to fraction: \( y = -\frac{1}{5}x + \frac{16}{5} \).
The point-slope form is flexible and easily converts to others, like the slope-intercept form.
Parallel Lines
Parallel lines offer an interesting relationship in geometry. Two lines are parallel if they have the same slope but different y-intercepts. This means parallel lines can go on infinitely without ever intersecting.
In the context of this exercise, we were dealing with a line parallel to \( x + 5y = 9 \). After converting the equation into slope-intercept form, we determined its slope as \(-\frac{1}{5}\).
  • Since parallel lines share the same slope, any line parallel to the original has the slope \(-\frac{1}{5}\).
  • The different y-intercept will depend on the specific point you use to derive this parallel line, as seen with our exercise.
Parallel lines are powerful in identifying lines that run alongside, which has practical implications, from railways to architecture. Understanding this concept helps us solve problems where direction, not position, is key.

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Most popular questions from this chapter

\(x\) intercept of 5 and slope of \(-\frac{3}{10}\)

If one line has a slope of \(\frac{2}{5}\), and another line has a slope of \(\frac{3}{7}\), which line is steeper? Explain your answer.

(a) Graph \(y=3 x+4, y=2 x+4, y=-4 x+4\), and \(y=-2 x+4\) on the same set of axes. (b) Graph \(y=\frac{1}{2} x-3, y=5 x-3, y=0.1 x-3\), and \(y=-7 x-3\) on the same set of axes. (c) What characteristic do all lines of the form \(y=a x+2\) (where \(a\) is any real number) share?

Now let's use a graphing calculator to get a graph of \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\). By letting \(\mathrm{F}=x\) and \(\mathrm{C}=y\), we obtain Figure 7.15. Pay special attention to the boundaries on \(x\). These values were chosen so that the fraction \(\frac{\text { (Maximum value of } x \text { ) minus (Minimum value of } x \text { ) }}{95}\) would be equal to 1 . The viewing window of the graphing calculator used to produce Figure \(7.15\) is 95 pixels (dots) wide. Therefore, we use 95 as the denominator of the fraction. We chose the boundaries for \(y\) to make sure that the cursor would be visible on the screen when we looked for certain values. \(7.2\) = Linear Inequalities in Two Variables 337 Now let's use the TRACE feature of the graphing calculator to complete the following table. Note that the cursor moves in increments of 1 as we trace along the graph. \begin{tabular}{l|lllllllll} \(\mathbf{F}\) & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline \(\mathbf{C}\) & & & & & & & & & \end{tabular} (This was accomplished by setting the aforementioned fraction equal to 1.) By moving the cursor to each of the F values, we can complete the table as follows. \begin{tabular}{r|rrrrrrrrr} \(\mathbf{F}\) & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline \(\mathbf{C}\) & \(-21\) & \(-15\) & \(-13\) & \(-12\) & \(-11\) & \(-7\) & \(-1\) & 7 & 16 \end{tabular} The \(C\) values are expressed to the nearest degree. Use your calculator and check the values in the table by using the equation \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\).

\(-2 x+y-3 \leq 0\)

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