/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Contains the point \((5,6)\) and... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Contains the point \((5,6)\) and is perpendicular to the \(y\) axis

Short Answer

Expert verified
The line equation is \( y = 6 \).

Step by step solution

01

Understanding the Problem

We need to find the equation of a line that contains the point (5,6) and is perpendicular to the y-axis. Recall that perpendicular to the y-axis means the line will be a horizontal line.
02

Identifying Line Characteristics

A line that is perpendicular to the y-axis is horizontal. Horizontal lines have a constant y-value and can be expressed with the equation \( y = c \), where \( c \) is a constant.
03

Applying the Point to Find the Line Equation

Since the line passes through the point \((5,6)\), the y-value of the line is 6. Therefore, substitute \( y = 6 \) in the equation of the line.
04

Writing the Line Equation

The equation of the line that passes through (5, 6) and is perpendicular to the y-axis is \( y = 6 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perpendicular Lines
Perpendicular lines are lines that intersect each other at a perfect right angle, which is 90 degrees. In coordinate geometry, this often means one line may have a negative reciprocal slope of another. However, when dealing with horizontal and vertical lines, their relationship is a bit different. A line perpendicular to the y-axis is not a vertical line, but rather a horizontal one. This is because a horizontal line runs parallel to the x-axis and does not slant upwards or downwards, keeping a consistent y-value at every point along it. The important thing to remember is direction:
  • Horizontal lines are perpendicular to the y-axis.
  • Vertical lines are perpendicular to the x-axis.
By understanding this, you can quickly identity that any line perpendicular to the y-axis is horizontal, balancing out how opposites attract in geometry!
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, involves graphing equations on a plane. The coordinate plane consists of two number lines: the x-axis, which is horizontal, and the y-axis, vertical. Together, these create a grid that can be used to plot points, lines, and shapes. Each point on this plane is expressed as a pair of numbers \(x,y\), representing its exact location.
Coordinate geometry lets us analyze the relationships between points and lines. For example:
  • To find a line parallel to an axis, notice if both coordinates stay constant or vary.
  • The slope determines the line's direction and steepness.
In our example, the line is perpendicular to the y-axis, meaning we primarily focus on manipulating the y-coordinate, while the x may vary. This gives great power in determining relationships simply from coordinates!
Equation of a Line
The equation of a line tells us mathematically how a line is positioned and angled within a coordinate plane. The most common form for a line's equation is the slope-intercept form: \(y = mx + b\), where \m\ is the slope and \b\ is the y-intercept. However, in the case of horizontal lines, the slope \(m\) is 0, because there is no vertical change as we move along the line. This simplifies the equation to \(y = c\), where \c\ is a constant y-value, indicating the uniform height of the line.
  • For vertical lines, the equation is \(x = a\), where \a\ is a constant x-value.
  • Horizontal line's equation depends solely on maintaining a constant y-coordinate.
When given a point like \(5,6\), and asked for a perpendicular line to the y-axis, the equation simply adopts the y-coordinate from the point, resulting in \(y = 6\). This showcases how straightforward it can be to pinpoint horizontal lines when perpendicularity to an axis is involved!

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Most popular questions from this chapter

Verify that the points \((-3,1),(5,7)\), and \((8,3)\) are vertices of a right triangle. [Hint: If \(a^{2}+b^{2}=c^{2}\), then it is a right triangle with the right angle opposite side \(c\).]

Graph \(|y|>1\).

Now let's use a graphing calculator to get a graph of \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\). By letting \(\mathrm{F}=x\) and \(\mathrm{C}=y\), we obtain Figure 7.15. Pay special attention to the boundaries on \(x\). These values were chosen so that the fraction \(\frac{\text { (Maximum value of } x \text { ) minus (Minimum value of } x \text { ) }}{95}\) would be equal to 1 . The viewing window of the graphing calculator used to produce Figure \(7.15\) is 95 pixels (dots) wide. Therefore, we use 95 as the denominator of the fraction. We chose the boundaries for \(y\) to make sure that the cursor would be visible on the screen when we looked for certain values. \(7.2\) = Linear Inequalities in Two Variables 337 Now let's use the TRACE feature of the graphing calculator to complete the following table. Note that the cursor moves in increments of 1 as we trace along the graph. \begin{tabular}{l|lllllllll} \(\mathbf{F}\) & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline \(\mathbf{C}\) & & & & & & & & & \end{tabular} (This was accomplished by setting the aforementioned fraction equal to 1.) By moving the cursor to each of the F values, we can complete the table as follows. \begin{tabular}{r|rrrrrrrrr} \(\mathbf{F}\) & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline \(\mathbf{C}\) & \(-21\) & \(-15\) & \(-13\) & \(-12\) & \(-11\) & \(-7\) & \(-1\) & 7 & 16 \end{tabular} The \(C\) values are expressed to the nearest degree. Use your calculator and check the values in the table by using the equation \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\).

Contains the point \((-2,-3)\) and is perpendicular to the line \(x+4 y=6\)

$$ \begin{array}{ll|llll} 2 x-y=6 & \mathbf{x} & -2 & 0 & 2 & 4 \\ \hline \mathbf{y} & & & & \end{array} $$

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