Chapter 6: Problem 75
Find each of the products and express the answers in the standard form of a complex number. $$ (9+6 i)(-1-i) $$
Short Answer
Expert verified
The product is \(-3 - 15i\).
Step by step solution
01
Apply the Distributive Property
First, apply the distributive property (also known as the FOIL method for two binomials) to expand the product:\[(9 + 6i)(-1 - i) = 9(-1) + 9(-i) + 6i(-1) + 6i(-i)\]
02
Perform Multiplication
Next, perform each multiplication:\[9(-1) = -9\]\[9(-i) = -9i\]\[6i(-1) = -6i\]\[6i(-i) = -6i^2\]
03
Simplify Using i² = -1
Remember that \(i^2 = -1\), so simplify \(-6i^2\) to get 6:\[-6i^2 = -6(-1) = 6\]
04
Combine Like Terms
Now combine all terms from the previous steps:\[ -9 - 9i - 6i + 6\]Combine the real parts and the imaginary parts separately:Real part: \(-9 + 6 = -3\)Imaginary part: \(-9i - 6i = -15i\)
05
Final Answer in Standard Form
Combine the simplified real part and imaginary part to write the complex number in standard form:\[-3 - 15i\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Distributive Property
The distributive property is a fundamental concept in algebra that allows us to multiply a single term by terms inside a parenthesis. When we're dealing with complex numbers, this property will extend to multiplying pairs of binomials. In our exercise, we have two binomials:
\(9(-1) + 9(-i) + 6i(-1) + 6i(-i)\).
By distributing this will yield four separate terms that we can then simplify and combine.
- The first is \(9 + 6i\) where \(9\) is the real part, and \(6i\) is the imaginary part.
- The second is \(-1 - i\), where \(-1\) is the real part, and \(-i\) is the imaginary part.
\(9(-1) + 9(-i) + 6i(-1) + 6i(-i)\).
By distributing this will yield four separate terms that we can then simplify and combine.
FOIL Method
The FOIL method is a specific application of the distributive property that helps with multiplying two binomials. The acronym "FOIL" stands for:
- First: - \(9 \times (-1) = -9\)
- Outer: - \(9 \times (-i) = -9i\)
- Inner: - \(6i \times (-1) = -6i\)
- Last: - \(6i \times (-i) = -6i^2\)
Each part is calculated separately, and then we combine the results to simplify the expression.
- First: Multiply the first terms in each binomial;
- Outer: Multiply the outer terms;
- Inner: Multiply the inner terms;
- Last: Multiply the last terms.
- First: - \(9 \times (-1) = -9\)
- Outer: - \(9 \times (-i) = -9i\)
- Inner: - \(6i \times (-1) = -6i\)
- Last: - \(6i \times (-i) = -6i^2\)
Each part is calculated separately, and then we combine the results to simplify the expression.
Imaginary Unit i
The imaginary unit \(i\) is a crucial concept in complex numbers. It stands for the square root of -1. Knowing the property \(i^2 = -1\) is essential when dealing with complex numbers. In the multiplication problem \(6i \times (-i)\), we have:
- The direct result is \(-6i^2\); because \(i^2 = -1\), we can substitute \(-1\) for \(i^2\).
- Simplifying gives:\(-6(-1) = 6\),changing the sign to the opposite.
Binomials Expansion
Expanding binomials involves taking two binomials and multiplying them to form a new polynomial. When dealing with complex numbers, this includes both real and imaginary parts. For\((9 + 6i)(-1 - i)\), we expand each binomial term-by-term, leading to the expression:\[-9 - 9i - 6i + 6\].To simplify, it's important to:
- Combine like terms – those that are similar in such nature, like real numbers with real numbers and imaginary with imaginary.
- Real parts: - Combine \(-9 + 6 = -3\)
- Imaginary parts: - Combine \(-9i - 6i = -15i\)