Chapter 6: Problem 7
Solve each quadratic equation using the method that seems most appropriate to you. $$ 2 x^{2}-3 x+4=0 $$
Short Answer
Expert verified
The solutions are complex: \(x = \frac{3 + i \sqrt{23}}{4}\) and \(x = \frac{3 - i \sqrt{23}}{4}\).
Step by step solution
01
Analyze the Equation
We are given the quadratic equation \(2x^2 - 3x + 4 = 0\). The coefficients are: \(a = 2\), \(b = -3\), and \(c = 4\). First, determine if the equation can be factored easily, which it cannot, due to the nature of the coefficients.
02
Use the Quadratic Formula
For a quadratic equation \(ax^2 + bx + c = 0\), the solutions can be found using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Substitute \(a = 2\), \(b = -3\), and \(c = 4\) into the formula.
03
Calculate the Discriminant
The discriminant of the quadratic equation is given by \(b^2 - 4ac\). Substitute the values: \((-3)^2 - 4 \cdot 2 \cdot 4\) which simplifies to \(9 - 32 = -23\). The negative discriminant indicates the roots are complex.
04
Find the Solutions Using Complex Numbers
Since the discriminant is negative, the solutions are complex. Substitute into the quadratic formula: \(x = \frac{-(-3) \pm \sqrt{-23}}{4}\) which simplifies to \(x = \frac{3 \pm i \sqrt{23}}{4}\) where \(i\) is the imaginary unit.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations, which take the form \(ax^2 + bx + c = 0\). It allows us to find the solutions, or roots, of the equation regardless of whether they are real or complex. The formula is:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula is derived from completing the square and is applicable when an equation cannot be easily factored.
To use the quadratic formula effectively:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula is derived from completing the square and is applicable when an equation cannot be easily factored.
To use the quadratic formula effectively:
- Identify the coefficients: \(a\), \(b\), and \(c\).
- Substitute these values into the formula.
- Calculate under the square root (the discriminant) to understand the nature of the roots.
Complex Roots
When a quadratic equation has a negative discriminant, the solutions are complex roots, which means they have both real and imaginary components. This happens because the square root of a negative number involves imaginary numbers.
In our specific example, the discriminant \(b^2 - 4ac\) resulted in a negative number, \(-23\).
Thus, the solutions are complex. The roots can be expressed in the form:
\[x = \frac{-b \pm i \sqrt{|b^2 - 4ac|}}{2a}\]Where \(i\) is the imaginary unit, representing \(\sqrt{-1}\).
Complex roots often appear in conjugate pairs, such as \(\frac{3 + i\sqrt{23}}{4}\) and \(\frac{3 - i\sqrt{23}}{4}\) in our example.
In our specific example, the discriminant \(b^2 - 4ac\) resulted in a negative number, \(-23\).
Thus, the solutions are complex. The roots can be expressed in the form:
\[x = \frac{-b \pm i \sqrt{|b^2 - 4ac|}}{2a}\]Where \(i\) is the imaginary unit, representing \(\sqrt{-1}\).
Complex roots often appear in conjugate pairs, such as \(\frac{3 + i\sqrt{23}}{4}\) and \(\frac{3 - i\sqrt{23}}{4}\) in our example.
Discriminant
The discriminant is a key element in the quadratic formula, given by \(b^2 - 4ac\). This value determines the nature of the roots of a quadratic equation. Depending on the sign of the discriminant, the roots can be:
- Positive: two distinct real roots
- Zero: one real root (a repeated root)
- Negative: two complex roots
Imaginary Numbers
Imaginary numbers are a mathematical concept that allows us to compute square roots of negative numbers. Denoted by \(i\), where \(i = \sqrt{-1}\). This is fundamental when dealing with complex roots in quadratic equations.
In our quadratic equation example, we found complex solutions because the discriminant was negative (\(-23\)).
The imaginary number \(i\) helped express the square root of this negative value, resulting in terms like \(i\sqrt{23}\).
Thus, imaginary numbers extend our number system, enabling a wider range of solutions for polynomial equations. Understanding this concept is crucial in advanced mathematics fields like engineering and physics, where complex numbers model real-world phenomena.
In our quadratic equation example, we found complex solutions because the discriminant was negative (\(-23\)).
The imaginary number \(i\) helped express the square root of this negative value, resulting in terms like \(i\sqrt{23}\).
Thus, imaginary numbers extend our number system, enabling a wider range of solutions for polynomial equations. Understanding this concept is crucial in advanced mathematics fields like engineering and physics, where complex numbers model real-world phenomena.