Chapter 6: Problem 53
Solve each quadratic equation using the method that seems most appropriate. $$ 3 x^{2}+5 x=-2 $$
Short Answer
Expert verified
The solutions are \(-\frac{2}{3}\) and \(-1\).
Step by step solution
01
Bring Equation into Standard Form
To use any method for solving a quadratic equation, we need it in standard form: \( ax^2 + bx + c = 0 \). The given equation is \( 3x^2 + 5x = -2 \). Add 2 to both sides to get: \( 3x^2 + 5x + 2 = 0 \).
02
Identify Coefficients
Identify the coefficients from the standard form \( ax^2 + bx + c = 0 \). Here, \( a = 3 \), \( b = 5 \), and \( c = 2 \).
03
Use the Quadratic Formula
The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute in the coefficients: \( x = \frac{-5 \pm \sqrt{5^2 - 4 \cdot 3 \cdot 2}}{2 \cdot 3} \).
04
Simplify Inside the Square Root
Calculate \( b^2 - 4ac \): \( 5^2 - 4 \cdot 3 \cdot 2 = 25 - 24 = 1 \). Now, substitute back: \( x = \frac{-5 \pm \sqrt{1}}{6} \).
05
Compute the Roots
Since \( \sqrt{1} = 1 \), the equation becomes \( x = \frac{-5 \pm 1}{6} \). This gives two solutions: \( x = \frac{-5 + 1}{6} = \frac{-4}{6} = -\frac{2}{3} \) and \( x = \frac{-5 - 1}{6} = \frac{-6}{6} = -1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations. These equations take the form \( ax^2 + bx + c = 0 \). The formula is used to find the values of \( x \) that satisfy the equation, commonly known as the "roots" of the equation. The quadratic formula is expressed as:
Solving quadratic equations using this formula involves:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Solving quadratic equations using this formula involves:
- Substituting the coefficients \( a \), \( b \), and \( c \) into the formula.
- Calculating the "discriminant," which is the expression under the square root: \( b^2 - 4ac \).
- Determining the square root of the discriminant.
- Applying the formula's plus-minus (\( \pm \)) symbol to find two potential root values.
Standard Form of Quadratic Equation
The standard form of a quadratic equation provides a consistent and clear way to express quadratic equations. This form is written as \( ax^2 + bx + c = 0 \), where:
In our original exercise, the equation started as \( 3x^2 + 5x = -2 \). By adding 2 to both sides, we convert it into standard form: \( 3x^2 + 5x + 2 = 0 \). This standard format made it possible to identify coefficients \( a \), \( b \), and \( c \) easily, which is crucial for applying the quadratic formula.
- \( a \), \( b \), and \( c \) are constants.
- \( a \) is not zero (otherwise the equation becomes linear, not quadratic).
- \( x \) represents the variable to be solved for.
In our original exercise, the equation started as \( 3x^2 + 5x = -2 \). By adding 2 to both sides, we convert it into standard form: \( 3x^2 + 5x + 2 = 0 \). This standard format made it possible to identify coefficients \( a \), \( b \), and \( c \) easily, which is crucial for applying the quadratic formula.
Roots of Quadratic Equation
Roots of a quadratic equation are the solutions to the equation \( ax^2 + bx + c = 0 \). These roots are the values of \( x \) that make the equation true. A quadratic equation typically has two roots, which can be real or complex numbers, depending on the discriminant.
The discriminant, \( b^2 - 4ac \), determines the nature of the roots.
The discriminant, \( b^2 - 4ac \), determines the nature of the roots.
- If the discriminant is positive, the equation has two distinct real roots.
- If it is zero, the equation has exactly one real root (a repeated root).
- If negative, the roots are complex and occur as a conjugate pair.