Chapter 6: Problem 33
Solve each equation. $$ x^{4}-18 x^{2}+72=0 $$
Short Answer
Expert verified
The solutions are \( \pm 2\sqrt{3} \) and \( \pm \sqrt{6} \).
Step by step solution
01
Identify the Quadratic Form
The given equation is \( x^4 - 18x^2 + 72 = 0 \). Notice that it can be viewed as a quadratic equation in terms of \( y = x^2 \). By substituting \( y = x^2 \), the equation transforms to \( y^2 - 18y + 72 = 0 \).
02
Solve the Quadratic Equation
Solve \( y^2 - 18y + 72 = 0 \) using the quadratic formula: \[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \( a = 1 \), \( b = -18 \), and \( c = 72 \). Calculate the discriminant: \( b^2 - 4ac = (-18)^2 - 4 \times 1 \times 72 = 324 - 288 = 36 \). So, \[ y = \frac{18 \pm \sqrt{36}}{2} = \frac{18 \pm 6}{2} \]. Thus, \( y = 12 \) or \( y = 6 \).
03
Solve for x in Terms of y
Since \( y = x^2 \), we now solve \( x^2 = 12 \) and \( x^2 = 6 \). For \( x^2 = 12 \): \( x = \pm \sqrt{12} = \pm 2\sqrt{3} \).For \( x^2 = 6 \): \( x = \pm \sqrt{6} \).
04
List All Solutions
The solutions to the original equation \( x^4 - 18x^2 + 72 = 0 \) are \( x = 2\sqrt{3}, \; -2\sqrt{3}, \; \sqrt{6}, \; -\sqrt{6} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a handy tool in algebra for understanding complex polynomial equations. Often, you can simplify a difficult equation by substituting one variable for another, leading to a more manageable form. In this exercise, we simplified the given quartic equation, \(x^4 - 18x^2 + 72 = 0\), by using the substitution \(y = x^2\).
This transformation changes a complex equation into a simpler quadratic one, \(y^2 - 18y + 72 = 0\). Here, the substitution helped us reduce the problem from dealing with an equation in \(x^4\) to one in \(y^2\), which is easier to solve.
This transformation changes a complex equation into a simpler quadratic one, \(y^2 - 18y + 72 = 0\). Here, the substitution helped us reduce the problem from dealing with an equation in \(x^4\) to one in \(y^2\), which is easier to solve.
- Always identify if a substitution can simplify your equation.
- Select appropriate values for substitution that naturally fit the structure of the equation.
- Translate back the substituted values to find the solution to the original equation.
Quadratic Formula
The quadratic formula is a powerful tool for finding solutions to quadratic equations of the form \(ax^2 + bx + c = 0\). In our transformed equation \(y^2 - 18y + 72 = 0\), it is used to find possible values of \(y\).
The formula itself is given by:
\[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
where \(a\), \(b\), and \(c\) are coefficients from our quadratic equation. For it to work smoothly:
The formula itself is given by:
\[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
where \(a\), \(b\), and \(c\) are coefficients from our quadratic equation. For it to work smoothly:
- Assign values to \(a\), \(b\), and \(c\) correctly. In this case, \(a = 1\), \(b = -18\), and \(c = 72\).
- Calculate the discriminant \(b^2 - 4ac\) to understand the nature of the roots.
- Solve the equation carefully, noting each plus and minus sign.
Discriminant
The discriminant, \(b^2 - 4ac\), is a component of the quadratic formula that determines the nature of a quadratic's roots. In the formula \(y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), the discriminant lies under the square root.
In our scenario, it was calculated as:
\[(-18)^2 - 4 \times 1 \times 72 = 324 - 288 = 36\]
This tells us how many solutions exist and what type they are:
In our scenario, it was calculated as:
\[(-18)^2 - 4 \times 1 \times 72 = 324 - 288 = 36\]
This tells us how many solutions exist and what type they are:
- If the discriminant is positive, like in this case (36), there are two distinct real roots.
- If it is zero, there is exactly one real repeated solution.
- If negative, the quadratic has no real solutions but two complex ones.