Chapter 6: Problem 30
Use the method of completing the square to solve each quadratic equation. $$ x^{2}+7 x+2=0 $$
Short Answer
Expert verified
The solutions are \( x = -\frac{7}{2} + \frac{\sqrt{41}}{2} \) and \( x = -\frac{7}{2} - \frac{\sqrt{41}}{2} \).
Step by step solution
01
Rearrange the Equation
Make sure the quadratic equation is in the standard form: \[ x^2 + 7x + 2 = 0 \] This equation is already in the correct form.
02
Identify Coefficients
Identify the coefficients in the equation: \[ a = 1, \ b = 7, \ c = 2 \] We are interested in the \(b\) term for completing the square.
03
Calculate the Term for Completing the Square
To complete the square, take half of the \( b \) coefficient, \(7\), and then square it. \[ \left( \frac{7}{2} \right)^2 = \frac{49}{4} \] This value will be used to complete the square.
04
Add and Subtract the Calculated Value
Add and subtract \( \frac{49}{4} \) inside the equation to maintain the equality:\[ x^2 + 7x + \frac{49}{4} - \frac{49}{4} + 2 = 0 \] This creates a perfect square trinomial within the equation.
05
Rewrite as a Perfect Square
Rewrite the equation:\[ \left( x + \frac{7}{2} \right)^2 - \frac{49}{4} + 2 = 0 \]
06
Simplify the Equation
Combine the constant terms:\[ \left( x + \frac{7}{2} \right)^2 = \frac{49}{4} - 2 \] \[ \frac{49}{4} - \frac{8}{4} = \frac{41}{4} \] The equation simplifies to:\[ \left( x + \frac{7}{2} \right)^2 = \frac{41}{4} \]
07
Solve for x by Taking the Square Root
Apply the square root to both sides of the equation:\[ x + \frac{7}{2} = \pm \sqrt{\frac{41}{4}} \] \[ x + \frac{7}{2} = \pm \frac{\sqrt{41}}{2} \]
08
Isolate x
Subtract \( \frac{7}{2} \) from both sides to solve for \( x \):\[ x = -\frac{7}{2} \pm \frac{\sqrt{41}}{2} \] This results in two possible solutions:\[ x = -\frac{7}{2} + \frac{\sqrt{41}}{2} \] \[ x = -\frac{7}{2} - \frac{\sqrt{41}}{2} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a type of polynomial equation that takes the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \) because if \( a \) equals zero, the equation becomes linear, not quadratic. Quadratics are prominent in algebra due to their distinct U-shaped graph known as a parabola.
Parabolas can open upwards or downwards depending on the sign of the coefficient \( a \):
Parabolas can open upwards or downwards depending on the sign of the coefficient \( a \):
- If \( a > 0 \), the parabola opens upwards.
- If \( a < 0 \), the parabola opens downwards.
Perfect Square Trinomial
A perfect square trinomial is a special form of a quadratic expression that can be written as the square of a binomial. It has the format \( (x + d)^2 \), which expands to \( x^2 + 2dx + d^2 \) upon multiplication. Recognizing a perfect square trinomial simplifies many algebraic processes, such as solving equations and factoring.
To create a perfect square trinomial from a typical quadratic equation \( ax^2 + bx + c \):
To create a perfect square trinomial from a typical quadratic equation \( ax^2 + bx + c \):
- Focus on the \( b \) term, which represents \( 2d \).
- Divide \( b \) by 2 to find \( d \), then square it to compute \( d^2 \).
Square Root Method
The square root method is a straightforward technique that can be used to solve quadratic equations, especially after a quadratic has been transformed into a perfect square trinomial form. This involves isolating the squared term and then applying the square root operation to both sides of the equation.
The process includes:
The process includes:
- Convert the equation into a form where the left-hand side is a perfect square trinomial.
- Isolate the square by rearranging any constants to the other side.
- Apply the square root to both sides: remember this introduces \( \pm \) because both positive and negative values are valid roots.