Chapter 6: Problem 13
Solve each quadratic equation using the method that seems most appropriate to you. $$ 2 x^{2}-4 x+7=0 $$
Short Answer
Expert verified
The roots are \(x = 1 + \frac{i\sqrt{10}}{2}\) and \(x = 1 - \frac{i\sqrt{10}}{2}\).
Step by step solution
01
Identify the Quadratic Equation
We are given the quadratic equation: \(2x^2 - 4x + 7 = 0\). We should determine the best method to solve it—factoring, completing the square, or using the quadratic formula. In this case, since the equation doesn't factor nicely and has non-simple integer coefficients, we'll use the quadratic formula.
02
Write Down the Quadratic Formula
The quadratic formula is given by \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a\), \(b\), and \(c\) are coefficients from the quadratic equation \(ax^2 + bx + c = 0\).
03
Identify Coefficients
From the equation \(2x^2 - 4x + 7 = 0\), we identify the coefficients as: \(a = 2\), \(b = -4\), and \(c = 7\).
04
Calculate the Discriminant
The discriminant of the quadratic equation is \(b^2 - 4ac\). Let's substitute the values: \((-4)^2 - 4(2)(7) = 16 - 56 = -40\). The discriminant is \(-40\), which indicates that the roots are complex numbers.
05
Substitute into the Quadratic Formula
Using the quadratic formula, we plug in the values: \(x = \frac{-(-4) \pm \sqrt{-40}}{2(2)} = \frac{4 \pm \sqrt{-40}}{4}\).
06
Simplify the Expression
The expression under the square root, \(\sqrt{-40}\), can be simplified. We know that \(\sqrt{-1} = i\), so \(\sqrt{-40} = \sqrt{-1 \times 4 \times 10} = 2i\sqrt{10}\). Substitute back: \(x = \frac{4 \pm 2i\sqrt{10}}{4}\).
07
Solve for Roots
Simplifying further, we get: \(x = \frac{4}{4} \pm \frac{2i\sqrt{10}}{4}\). So, \(x = 1 \pm \frac{i\sqrt{10}}{2}\). Therefore, the roots are \(x = 1 + \frac{i\sqrt{10}}{2}\) and \(x = 1 - \frac{i\sqrt{10}}{2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations. A quadratic equation is typically written in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. Using the quadratic formula, \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]we can find the values of \(x\) that satisfy the equation by plugging in these constants. The formula works universally for any quadratic equation, making it extremely useful.
- "\(b^2 - 4ac\)" is called the discriminant, which determines the nature of the equation's roots.
- "\(-b \pm\)" indicates that there will be two potential solutions: one with the plus symbol and one with the minus symbol.
Complex Numbers
When solving quadratic equations, especially those with a negative discriminant, we encounter complex numbers. Complex numbers are numbers that include the imaginary unit \(i\), which represents the square root of \(-1\). Thus, a complex number is typically of the form \(a + bi\), where \(a\) and \(b\) are real numbers.
- Complex numbers allow us to find solutions to equations that don't intersect the x-axis on a graph.
- The imaginary unit \(i\) makes it possible to handle square roots of negative numbers.
Discriminant in Quadratic Equations
The discriminant in a quadratic equation, given by \(b^2 - 4ac\), is a key value that provides insight into the nature of the roots of the equation. Depending on its value, the discriminant can indicate different types of solutions:
- If \(b^2 - 4ac > 0\), the quadratic equation has two distinct real roots.
- If \(b^2 - 4ac = 0\), there is exactly one real root, also known as a repeated or double root.
- If \(b^2 - 4ac < 0\), the equation has complex roots, involving imaginary numbers.