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Simplify each numerical expression. \(2^{-4}+5^{-1}\)

Short Answer

Expert verified
The simplified expression is \( \frac{21}{80} \).

Step by step solution

01

Simplify the First Term

Understand and simplify the first component of the expression, which is \(2^{-4}\). Recall that a negative exponent can be rewritten as a reciprocal of the positive exponent. Therefore, \(2^{-4} = \frac{1}{2^4}\). Calculate \(2^4 = 2 \times 2 \times 2 \times 2 = 16\), so \(2^{-4} = \frac{1}{16}\).
02

Simplify the Second Term

Now, simplify the second component, which is \(5^{-1}\). Similarly, negative exponents denote the reciprocal of the base raised to the corresponding positive power. Therefore, \(5^{-1} = \frac{1}{5^1} = \frac{1}{5}\).
03

Combine the Simplified Terms

Add the two simplified fractions from the previous steps. We have \(\frac{1}{16} + \frac{1}{5}\). To perform this addition, we need a common denominator. The least common multiple of 16 and 5 is 80.
04

Convert to a Common Denominator

Convert \(\frac{1}{16}\) and \(\frac{1}{5}\) to equivalent fractions with a common denominator of 80. Calculate \(\frac{1}{16} = \frac{5}{80}\) and \(\frac{1}{5} = \frac{16}{80}\). We do this by multiplying the numerator and denominator of \(\frac{1}{16}\) by 5, and for \(\frac{1}{5}\), by 16.
05

Add the Fractions

Now, add the fractions with the common denominator: \(\frac{5}{80} + \frac{16}{80} = \frac{5+16}{80} = \frac{21}{80}\).
06

Simplify if Possible

Check if \(\frac{21}{80}\) can be further simplified. Since 21 and 80 have no common factors other than 1, the fraction is already in its simplest form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negative Exponents
Negative exponents can seem confusing at first, but they have a straightforward rule to follow. When you see a negative exponent, it means you take the reciprocal of the base raised to the positive of that exponent. For example, with \(2^{-4}\), you switch from \(2\) raised to the negative fourth power to its reciprocal, which is \(\frac{1}{2^4}\).
Here's a simple step-by-step:
  • Identify the negative exponent, such as in \(5^{-1}\).
  • Rewrite the expression using the reciprocal, \(5^{-1} = \frac{1}{5}\).
  • Calculate the positive power of the base, like \(2^4 = 16\).
  • Wrap it up to get, \(2^{-4} = \frac{1}{16}\).
These basics make handling negative exponents much easier!
Fractions
Fractions represent a part of a whole and are composed of a numerator over a denominator, like \(\frac{a}{b}\). In the context of simplifying expressions with negative exponents, fractions come into play when rewriting and adding terms.
When you simplify an expression with negative exponents, like \(2^{-4}\) and \(5^{-1}\), you convert these into fractions. Specifically, \(2^{-4}\) becomes \(\frac{1}{16}\), and \(5^{-1}\) becomes \(\frac{1}{5}\).
Understanding fractions deeply:
  • The **denominator** tells how many equal parts the whole is divided into.
  • The **numerator** shows how many parts we are considering.
  • Adding fractions requires a common denominator.
Mastering fractions is crucial to dealing with any math involving parts!
Least Common Denominator
The least common denominator (LCD) is a helpful concept when adding or subtracting fractions. It is the smallest shared multiple in the denominators of the fractions involved. When you combine fractions like \(\frac{1}{16}\) and \(\frac{1}{5}\), your goal is to make the denominators the same.
Here's how to find the least common denominator:
  • List multiples of each denominator. For \(16\) and \(5\), those are:
    • 16: 16, 32, 48, 64, 80, ...
    • 5: 5, 10, 15, 20, 25, 30, 80, ...
  • Identify the smallest common multiple, which here is \(80\).
  • Convert each fraction to an equivalent fraction with this common denominator:
    • \(\frac{1}{16} = \frac{5}{80}\)
    • \(\frac{1}{5} = \frac{16}{80}\)
After these conversions, adding fractions becomes a matter of combining numerators. For these fractions, the sum gives \(\frac{21}{80}\), a straightforward addition once each fraction shares a denominator!

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