Chapter 4: Problem 49
For Problems \(13-66\), add or subtract the rational expressions as indicated. Be sure to express your answers in simplest form. $$ \frac{2 x}{x-1}+\frac{3}{x} $$
Short Answer
Expert verified
\(\frac{2x^2 + 3x - 3}{x(x-1)}\) is the simplest form.
Step by step solution
01
Find a Common Denominator
The denominators of the rational expressions are \(x - 1\) and \(x\). To add the fractions, we need a common denominator. The least common denominator (LCD) is \((x - 1)(x)\).
02
Rewrite Each Fraction with the LCD
Multiply the numerator and the denominator of each fraction by whatever is missing from their denominators to achieve the LCD:1. For \(\frac{2x}{x-1}\), multiply both the top and bottom by \(x\) to get:\[ \frac{2x \cdot x}{(x-1)\cdot x} = \frac{2x^2}{x(x-1)} \]2. For \(\frac{3}{x}\), multiply both the top and bottom by \((x - 1)\) to get:\[ \frac{3 \cdot (x - 1)}{x (x-1)} = \frac{3x - 3}{x(x-1)} \]
03
Combine the Fractions
Add the fractions by combining their numerators over the common denominator:\[ \frac{2x^2}{x(x-1)} + \frac{3x - 3}{x(x-1)} = \frac{2x^2 + 3x - 3}{x(x-1)} \]
04
Simplify the Expression
Check for any common factors in the numerator to simplify further. The expression \(2x^2 + 3x - 3\) does not factor neatly to have any common factors with the denominator, so it stays as is.
05
Express in Simplest Form
The simplest form of the expression is:\[ \frac{2x^2 + 3x - 3}{x(x-1)} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Common Denominator
When dealing with rational expressions, much like with fractions, finding a common denominator is crucial for adding or subtracting them.
For example, in general fractions such as \(\frac{1}{2} + \frac{1}{3}\), the denominators are different—2 and 3. To combine them, we must find a common multiple of these denominators.
The same idea applies to rational expressions that involve variables.
Imagine you have the rational expressions \(\frac{2x}{x-1}\) and \(\frac{3}{x}\). Here, the denominators are \(x-1\) and \(x\).
To add these expressions, we determine the least common denominator (LCD).
For example, in general fractions such as \(\frac{1}{2} + \frac{1}{3}\), the denominators are different—2 and 3. To combine them, we must find a common multiple of these denominators.
The same idea applies to rational expressions that involve variables.
Imagine you have the rational expressions \(\frac{2x}{x-1}\) and \(\frac{3}{x}\). Here, the denominators are \(x-1\) and \(x\).
To add these expressions, we determine the least common denominator (LCD).
- The LCD is the smallest expression that both \(x-1\) and \(x\) can divide into, without leaving a remainder.
- In this case, it is simply their product: \((x-1) \cdot x\).
Simplifying Expressions
Simplifying expressions is a key step in the process of working with rational expressions.
After finding a common denominator, the next step involves rewriting each fraction to reflect this common denominator.
For example, if you have \(\frac{2x}{x-1}\) and \(\frac{3}{x}\), the LCD is \((x-1)x\).
Thus, you would adjust each expression accordingly to match this.
Remember: simplifying is about clarity and minimizing complexity.
After finding a common denominator, the next step involves rewriting each fraction to reflect this common denominator.
For example, if you have \(\frac{2x}{x-1}\) and \(\frac{3}{x}\), the LCD is \((x-1)x\).
Thus, you would adjust each expression accordingly to match this.
- For \(\frac{2x}{x-1}\): Multiply both the numerator and denominator by \(x\), resulting in \(\frac{2x^2}{x(x-1)}\).
- For \(\frac{3}{x}\): Multiply both the numerator and denominator by \(x-1\), resulting in \(\frac{3(x-1)}{x(x-1)} = \frac{3x-3}{x(x-1)}\).
Remember: simplifying is about clarity and minimizing complexity.
- This often means combining like terms and trying to factor expressions where possible. In our case, further simplification was not possible beyond combining the terms under a single denominator.
Adding Fractions
Adding fractions, whether they're numerical or involve variables like in rational expressions, follows the same principle:
Once you have a common denominator, the addition occurs over that shared base.
In our example, the two modified fractions become \(\frac{2x^2}{x(x-1)}\) and \(\frac{3x-3}{x(x-1)}\).
Add, subtract, multiply, or divide the coefficients as needed but keep an eye on variable terms, ensuring they are correctly combined.
For the rational expression in question, this results in a single, streamlined expression that has been simplified where possible: \[ \frac{2x^2 + 3x - 3}{x(x-1)} \].
Although this expression didn’t simplify further through factoring, it exemplifies the concept of merging through addition after achieving a common denominator.
Once you have a common denominator, the addition occurs over that shared base.
In our example, the two modified fractions become \(\frac{2x^2}{x(x-1)}\) and \(\frac{3x-3}{x(x-1)}\).
- Since the denominators are now the same, the fractions can be combined by adding the numerators.
- Thus, you find \(\frac{2x^2 + (3x - 3)}{x(x-1)}\).
Add, subtract, multiply, or divide the coefficients as needed but keep an eye on variable terms, ensuring they are correctly combined.
For the rational expression in question, this results in a single, streamlined expression that has been simplified where possible: \[ \frac{2x^2 + 3x - 3}{x(x-1)} \].
Although this expression didn’t simplify further through factoring, it exemplifies the concept of merging through addition after achieving a common denominator.