Chapter 4: Problem 37
For Problems \(11-52\), perform the indicated divisions. $$ \frac{8 y^{3}-y^{2}-y+5}{y^{2}+y} $$
Short Answer
Expert verified
The result is \(8y - 9 + \frac{8y + 5}{y^2 + y}\).
Step by step solution
01
Set Up the Division
We're dividing the polynomial \(8y^3 - y^2 - y + 5\) by the polynomial \(y^2 + y\). We'll perform polynomial long division, sometimes referred to as synthetic division for polynomials. Begin by writing the division in polynomial long division format, with \(8y^3 - y^2 - y + 5\) under the division symbol and \(y^2 + y\) outside.
02
Divide the Leading Terms
Divide the leading term of the dividend, \(8y^3\), by the leading term of the divisor, \(y^2\). This gives \(8y\). Place this as the first term of the quotient above the division symbol.
03
Multiply and Subtract
Multiply the entire divisor \(y^2 + y\) by the term you just found, \(8y\). This gives \(8y \cdot (y^2 + y) = 8y^3 + 8y^2\). Subtract this result from the original polynomial starting beneath the dividend: \((8y^3 - y^2 - y + 5) - (8y^3 + 8y^2)\). The result is \(-9y^2 - y + 5\).
04
Repeat the Process
With the new polynomial \(-9y^2 - y + 5\), divide the leading term \(-9y^2\) by the leading term of the divisor \(y^2\). This gives \(-9\), which becomes the next term in the quotient. Multiply the entire divisor \(y^2 + y\) by \(-9\) and subtract the result \(-9(y^2 + y) = -9y^2 - 9y\) from \(-9y^2 - y + 5\). The result is \(8y + 5\).
05
Finalize the Division
Since the degree of the remaining polynomial \(8y + 5\) is less than the degree of the divisor \(y^2 + y\), this is the remainder of the division. Therefore, the division gives: \(8y - 9 + \frac{8y + 5}{y^2 + y}\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Division
Polynomial division is a process similar to long division with numbers, but instead, we work with polynomials. The goal is to divide a larger polynomial by another polynomial, called the divisor, resulting in a quotient and possibly a remainder. This approach helps simplify expressions and solve polynomial equations by breaking them down into smaller components.
In the exercise, we're dividing the polynomial \(8y^3 - y^2 - y + 5\) by \(y^2 + y\). ### Steps in Polynomial Division
With the given polynomials, the division results in \(8y - 9\) with a remainder \(\frac{8y + 5}{y^2 + y}\).
In the exercise, we're dividing the polynomial \(8y^3 - y^2 - y + 5\) by \(y^2 + y\). ### Steps in Polynomial Division
- **Setup**: Arrange the polynomials in descending order of degree and write them in a long division format.
- **Divide** the leading term of the dividend by the leading term of the divisor to find the first term of the quotient.
- **Multiply** the entire divisor by this term and subtract the result from the dividend, reducing the polynomial's degree.
- **Repeat** the process with the new polynomial until the remainder is of a lesser degree than the divisor.
With the given polynomials, the division results in \(8y - 9\) with a remainder \(\frac{8y + 5}{y^2 + y}\).
Intermediate Algebra
Intermediate algebra deals with the concepts that serve as a foundation for higher-level mathematics, including polynomials. One of the key skills in intermediate algebra is mastering polynomial division, as it often comes up in various problems and applications.### Importance in Algebra
- **Foundation**: Understanding polynomial division strengthens your ability to handle complex equations.
- **Quadratic Equations**: It often helps when working with quadratic functions, especially when determining their roots or simplifying expressions.
- **Function Analysis**: Skills in polynomial division are critical when performing operations with functions, such as finding asymptotes and intercepts.
Synthetic Division
Synthetic division is a simplified form of polynomial division, typically used when dividing a polynomial by a linear binomial of the form \(x - c\). It is a quicker and more straightforward method than long division in these specific cases but isn't applicable for dividing by polynomials with degree higher than one.### When to Use Synthetic Division
- **Linear Divisors**: Only applicable when the divisor is a linear polynomial, \(x - c\).
- **Simplicity**: Reduces computation steps, especially useful for large coefficients or degrees.
- **Efficiency**: Useful for checking factors quickly or evaluating polynomials at specific points.