Chapter 4: Problem 30
For Problems \(1-44\), solve each equation. $$ \frac{x}{-4}=\frac{3}{12 x-25} $$
Short Answer
Expert verified
The solutions are \(x = \frac{4}{3}\) and \(x = \frac{3}{4}\).
Step by step solution
01
Understand the Problem
We need to solve the equation \( \frac{x}{-4}=\frac{3}{12x-25} \). The goal is to find the value of \(x\) that makes this equation true.
02
Cross Multiply
In the equation \( \frac{x}{-4} = \frac{3}{12x-25} \), cross-multiply to eliminate the fractions: \(x(12x-25) = 3(-4)\). This becomes \(12x^2 - 25x = -12\).
03
Rearrange the Equation
Move all terms to one side of the equation to make it a standard quadratic equation: \(12x^2 - 25x + 12 = 0\).
04
Apply the Quadratic Formula
For the quadratic equation \(ax^2 + bx + c = 0\), use the formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Here, \(a = 12\), \(b = -25\), and \(c = 12\).
05
Calculate the Discriminant
Compute the discriminant \(b^2 - 4ac\): \((-25)^2 - 4(12)(12) = 625 - 576 = 49\).
06
Solve for x using the Quadratic Formula
Since the discriminant is 49, we have two real solutions: \(x = \frac{-(-25) \pm \sqrt{49}}{2(12)}\). Solve for both solutions, \(x = \frac{25 \pm 7}{24}\).
07
Find the Two Possible Solutions
Compute both solutions: \(x = \frac{25 + 7}{24} = \frac{32}{24} = \frac{4}{3}\) and \(x = \frac{25 - 7}{24} = \frac{18}{24} = \frac{3}{4}\).
08
Verify the Solutions
Plug \(x = \frac{4}{3}\) and \(x = \frac{3}{4}\) back into the original equation to ensure they satisfy it. Both values make the equation true, confirming they are correct solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Multiplication
Cross multiplication is a technique used to solve equations that involve two fractions set equal to each other. This method helps to eliminate the fractions, making the equation easier to solve.
- Cross-multiplication works by multiplying across the equation diagonally. In other words, you multiply the numerator of one fraction by the denominator of the other fraction.
- For our problem, we have \( \frac{x}{-4} = \frac{3}{12x-25} \). To cross-multiply, multiply \(x\) by \(12x - 25\) and \(-4\) by \(3\).
- This results in the equation \(x(12x-25) = 3(-4)\), which simplifies to \(12x^2 - 25x = -12\).
Quadratic Formula
The quadratic formula is a powerful tool for finding the solutions to any quadratic equation of the form \(ax^2 + bx + c = 0\). This formula is especially useful when the equation cannot be easily factored. The quadratic formula is given as:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
- In our equation, \(12x^2 - 25x + 12 = 0\), we identify \(a = 12\), \(b = -25\), and \(c = 12\).
- Substitute these values into the formula to solve for \(x\).
- Using the formula, substitute to find \(x = \frac{-(-25) \pm \sqrt{49}}{24}\).
Discriminant Calculation
The discriminant is a part of the quadratic formula that allows us to determine the number and type of solutions for a quadratic equation. It is calculated from the expression \(b^2 - 4ac\).
- The discriminant is crucial as it tells us whether the solutions to the quadratic equation are real or complex.
- In this problem, we calculate the discriminant as \((-25)^2 - 4(12)(12) = 625 - 576 = 49\).
- Positive, as in our case (49), there are two distinct real solutions.
- Zero, there is exactly one real solution, meaning it's a perfect square trinomial.
- Negative, there are no real solutions; instead, the solutions are complex numbers.