Chapter 10: Problem 23
Use Cramer's rule to find the solution set for each of the following systems. (Objective 2) $$ \left(\begin{array}{rr} -x+3 y= & 17 \\ 4 x-5 y= & -33 \end{array}\right) $$
Short Answer
Expert verified
The solution set is \(x = -2\), \(y = 5\).
Step by step solution
01
Write the System in Matrix Form
The given system of equations is: \(-x + 3y = 17\) and \(4x - 5y = -33\). This can be written in matrix form as \(A\mathbf{x} = \mathbf{b}\), where \(A = \begin{pmatrix} -1 & 3 \ 4 & -5 \end{pmatrix}\), \(\mathbf{x} = \begin{pmatrix} x \ y \end{pmatrix}\), and \(\mathbf{b} = \begin{pmatrix} 17 \ -33 \end{pmatrix}\).
02
Calculate the Determinant of A
The determinant of matrix \(A\), denoted as \(\det(A)\), is calculated as: \[ \det(A) = (-1)(-5) - (3)(4) = 5 - 12 = -7. \]
03
Formulate Matrices A_x and A_y
To apply Cramer's rule, substitute the first column of \(A\) with \(\mathbf{b}\) to form \(A_x\): \[ A_x = \begin{pmatrix} 17 & 3 \ -33 & -5 \end{pmatrix}. \] Similarly, substitute the second column of \(A\) with \(\mathbf{b}\) to form \(A_y\): \[ A_y = \begin{pmatrix} -1 & 17 \ 4 & -33 \end{pmatrix}. \]
04
Calculate the Determinants of A_x and A_y
Calculate the determinants of \(A_x\) and \(A_y\):\[ \det(A_x) = (17)(-5) - (3)(-33) = -85 + 99 = 14, \]\[ \det(A_y) = (-1)(-33) - (17)(4) = 33 - 68 = -35. \]
05
Apply Cramer's Rule to Find x and y
Using Cramer's Rule, the solution for \(x\) is given by \(x = \frac{\det(A_x)}{\det(A)}\) and for \(y\) by \(y = \frac{\det(A_y)}{\det(A)}\):\[ x = \frac{14}{-7} = -2, \]\[ y = \frac{-35}{-7} = 5. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Determinants in Algebra
Determinants in algebra play a crucial role when it comes to solving systems of linear equations. Mathematically, a determinant is a special number calculated from a square matrix. In this context, it helps determine if a system of equations has a unique solution.
In our example, the matrix \( A = \begin{pmatrix} -1 & 3 \ 4 & -5 \end{pmatrix} \) is associated with the system of equations we are solving. To find the determinant of this matrix, apply the formula for a 2x2 matrix:
A non-zero determinant \( \det(A) \) indicates that the system has a unique solution. If it were zero, it would suggest either no solutions or infinitely many solutions.
In our example, the matrix \( A = \begin{pmatrix} -1 & 3 \ 4 & -5 \end{pmatrix} \) is associated with the system of equations we are solving. To find the determinant of this matrix, apply the formula for a 2x2 matrix:
- \( \det(A) = a\cdot d - b\cdot c \)
- Where \(a, b, c,\) and \(d\) are the elements of the matrix \( A \)
A non-zero determinant \( \det(A) \) indicates that the system has a unique solution. If it were zero, it would suggest either no solutions or infinitely many solutions.
Solving Systems of Linear Equations
A system of linear equations consists of two or more equations with multiple variables. These equations represent straight lines in a graph and finding their solution means finding the point(s) where these lines intersect. In the given example, the system is composed of:
By calculating the determinants of these auxiliary matrices and substituting them into Cramer's formula, we derive the values of \(x\) and \(y\). The solution \((x = -2, y = 5)\) represents the intersection point of the lines formed by the equations.
- \(-x + 3y = 17\)
- \(4x - 5y = -33\)
By calculating the determinants of these auxiliary matrices and substituting them into Cramer's formula, we derive the values of \(x\) and \(y\). The solution \((x = -2, y = 5)\) represents the intersection point of the lines formed by the equations.
Matrix Representation of a System
Matrix representation simplifies solving systems of linear equations by making them compact and organized, which is beneficial in both manual calculations and computer algorithms. A system of equations like:
- \(-x + 3y = 17\)
- \(4x - 5y = -33\)
- \(A = \begin{pmatrix} -1 & 3 \ 4 & -5 \end{pmatrix}\)
- \(\mathbf{x} = \begin{pmatrix} x \ y \end{pmatrix}\)
- \(\mathbf{b} = \begin{pmatrix} 17 \ -33 \end{pmatrix}\)