Chapter 10: Problem 12
For Problems \(1-26\), solve each system by using the substitution method. (Objective 1) $$ \left(\begin{array}{c} y=\frac{3}{4} x-5 \\ 5 x-4 y=9 \end{array}\right) $$
Short Answer
Expert verified
The solution is \( x = -\frac{11}{2} \), \( y = -\frac{73}{8} \).
Step by step solution
01
Identify the Equations
We have two equations in the system: the first equation is \( y = \frac{3}{4}x - 5 \) and the second equation is \( 5x - 4y = 9 \).
02
Substitute for y
From the first equation, we already have \( y \) expressed in terms of \( x \). Substitute \( y = \frac{3}{4}x - 5 \) into the second equation: \( 5x - 4(\frac{3}{4}x - 5) = 9 \).
03
Simplify After Substitution
Distribute the \( -4 \) in the second equation: \( 5x - 3x + 20 = 9 \). Simplifying gives: \( 2x + 20 = 9 \).
04
Solve for x
Subtract 20 from both sides: \( 2x = 9 - 20 \). Simplify to get \( 2x = -11 \). Divide both sides by 2 to find \( x = -\frac{11}{2} \).
05
Substitute to Find y
Use the expression for \( y \) from Step 1: \( y = \frac{3}{4}x - 5 \). Substitute \( x = -\frac{11}{2} \) into this expression: \( y = \frac{3}{4}(-\frac{11}{2}) - 5 \).
06
Simplify to Find y
Calculate \( y = -\frac{33}{8} - 5 \). Convert 5 to \( \frac{40}{8} \), so \( y = -\frac{33}{8} - \frac{40}{8} \). Simplify to get \( y = -\frac{73}{8} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Systems of Equations
A system of equations is a set of two or more equations that share the same variables. In other words, these equations are inter-related and must be solved together to find common values for the variables involved. For example, in the provided exercise, the variables are \( x \) and \( y \), and their values must satisfy both equations simultaneously.
To solve a system of equations, there are several methods available:
To solve a system of equations, there are several methods available:
- Substitution Method: This involves expressing one variable in terms of the other using one equation and then substituting it into the other equation.
- Elimination Method: This technique involves adding or subtracting equations in order to cancel out one of the variables, making it possible to solve for the other.
- Graphical Method: You plot both equations on the same graph to find the point(s) of intersection, which represents the solution.
Linear Equations
Linear equations are equations that form a straight line when graphed. They come in the form of \( ax + by = c \), where \( a \), \( b \), and \( c \) are constants, and \( x \) and \( y \) are variables. In a two-variable linear equation, the highest power of each variable is one.
The system in this exercise consists of linear equations:
The system in this exercise consists of linear equations:
- The first equation \( y = \frac{3}{4}x - 5 \) is in slope-intercept form, which makes it very easy to express \( y \) in terms of \( x \).
- The second equation \( 5x - 4y = 9 \) is in standard form. This equation didn't explicitly solve for either variable initially, but it is integral to finding the solution when combined with the first equation.
- At a single point, indicating one unique solution.
- Everywhere, indicating infinitely many solutions, typical of identical equations.
- Nowhere, implying the lines are parallel and there is no solution.
Step-by-Step Algebra Solutions
One of the most effective ways to understand algebra is through step-by-step solutions. By unraveling each step clearly, students can follow and understand the logic behind each operation. Let's walk through the process used in the provided solution:
First, we identified the equations we want to solve. By labeling \( y = \frac{3}{4}x - 5 \) as the easier equation to manipulate, it was used for substitution into the second equation.
We then replaced \( y \) in \( 5x - 4y = 9 \) using the expression from the first equation, effectively reducing the system to a single linear equation with one variable, \( x \).
After performing operations such as distribution and simplification, we solved for \( x \). Subsequent steps involved substituting back that value into the equation for \( y \) and solving, ultimately finding a numeric value for \( y \).
Each of these steps ensures the process is transparent and reinforces the logical flow of solving systems of equations through substitution. Structured step-by-step solutions are invaluable for mastering algebra, as they offer clarity and allow students to check their work against a reliable process.
First, we identified the equations we want to solve. By labeling \( y = \frac{3}{4}x - 5 \) as the easier equation to manipulate, it was used for substitution into the second equation.
We then replaced \( y \) in \( 5x - 4y = 9 \) using the expression from the first equation, effectively reducing the system to a single linear equation with one variable, \( x \).
After performing operations such as distribution and simplification, we solved for \( x \). Subsequent steps involved substituting back that value into the equation for \( y \) and solving, ultimately finding a numeric value for \( y \).
Each of these steps ensures the process is transparent and reinforces the logical flow of solving systems of equations through substitution. Structured step-by-step solutions are invaluable for mastering algebra, as they offer clarity and allow students to check their work against a reliable process.