Chapter 9: Problem 97
Graph each function by finding ordered pair solutions, plotting the solutions, and then drawing a smooth curve through the plotted points. Graph \(f(x)=e^{x}(\text { Exercise } 79), f(x)=e^{x}+2(\text { Exercise } 83)\) and \(f(x)=e^{x}-3(\text { Exercise } 84)\) on the same screen. Discuss any trends shown on the graphs.
Short Answer
Step by step solution
Understand the Functions
Create a Table of Values for \(f(x) = e^x\)
Plot Points and Graph \(f(x) = e^x\)
Create a Table of Values for \(f(x) = e^x + 2\)
Plot Points and Graph \(f(x) = e^x + 2\)
Create a Table of Values for \(f(x) = e^x - 3\)
Plot Points and Graph \(f(x) = e^x - 3\)
Analyze Trends and Discuss
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing
In these exercises, the function \( f(x) = e^x \) serves as the base graph, representing the simplest form of an exponential function with the base \( e \). This base function starts increasing slowly at negative \( x \) values and grows very rapidly as \( x \) becomes positive, reflecting how exponential growth accelerates.
When plotting this function:
- Identify key points such as \( (0, 1) \), since \( e^0 = 1 \),
- Calculate a few more points, like \( f(-1) \approx 0.368 \) and \( f(1) \approx 2.718 \).
Remember, exponential graphs are defined everywhere, never hitting the \( x \)-axis, and they move upwards swiftly towards positive infinity with increasing \( x \).
Vertical Translations
For the functions in the exercise, \( f(x) = e^x + 2 \) and \( f(x) = e^x - 3 \) illustrate vertical translations. Adding 2 to the base function \( e^x \) shifts the entire graph up by 2 units. Similarly, subtracting 3 lowers the graph by 3 units. These transformations affect the \( y \)-values directly while keeping the same \( x \)-values.
Take these points into consideration:
- For \( f(x) = e^x + 2 \): each \( y \)-coordinate from \( f(x) = e^x \) increases by 2.
- In \( f(x) = e^x - 3 \), each \( y \)-coordinate decreases by 3.
Consequently, the \( y \)-intercepts for \( f(x) = e^x + 2 \) and \( f(x) = e^x - 3 \) are at \( (0, 3) \) and \( (0, -2) \), respectively, showing how the entire curves move vertically.
Natural Logarithm
Exponential functions are key tools in various fields because they describe rapid growth patterns. However, when solving for \( x \) in an equation like \( e^x = a \), you'd employ the natural logarithm: \( x = \ln(a) \).
\( \ln(x) \) has a special property:
- \( \ln(1) = 0 \)
- If \( e^x = y \), then \( \ln(y) = x \)
Understanding this relationship is crucial for more advanced studies, as the natural logarithm helps in analyzing the behavior and analysis of exponential growth, modeling natural processes, and solving real-world problems related to growth and decay.