/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Solve. If \(f(x)=x^{3}-5,\) sh... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve. If \(f(x)=x^{3}-5,\) show that \(f^{-1}(x)=\sqrt[3]{x+5}\)

Short Answer

Expert verified
The inverse is \( f^{-1}(x)=\sqrt[3]{x+5} \).

Step by step solution

01

Understand the Problem

We are given the function \( f(x) = x^3 - 5 \) and need to show that its inverse \( f^{-1}(x) \) is \( \sqrt[3]{x+5} \). This means we want to find a function that, when composed with \( f(x) \), yields \( x \).
02

Expressing the Inverse Function

To find the inverse function \( f^{-1}(x) \), we start by setting \( y = f(x) = x^3 - 5 \). The goal is to solve this equation for \( x \) in terms of \( y \).
03

Rearrange the Equation

Starting from \( y = x^3 - 5 \), add 5 to both sides of the equation to isolate the \( x^3 \) term: \( y + 5 = x^3 \).
04

Solve for x

Take the cube root of both sides to solve for \( x \): \( x = \sqrt[3]{y + 5} \). This expression gives us \( f^{-1}(y) = \sqrt[3]{y + 5} \).
05

Verify the Inverse Relationship

To verify that \( f^{-1}(x) = \sqrt[3]{x+5} \) is correct, compose \( f \) and \( f^{-1} \): calculate \( f(f^{-1}(x)) \) and check if it equals \( x \).
06

Composing and Simplifying the Functions

Compute \( f(f^{-1}(x)) = f(\sqrt[3]{x+5}) = (\sqrt[3]{x+5})^3 - 5 \). Simplifying gives: \( x + 5 - 5 = x \). This confirms that \( f(f^{-1}(x)) = x \).
07

Conclusion

Since \( f(f^{-1}(x)) = x \), \( f^{-1}(x) = \sqrt[3]{x+5} \) is indeed the correct inverse of \( f(x) = x^3 - 5 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cube Roots
Cube roots are about finding a number that, when multiplied by itself three times, gives the original number. For example, the cube root of 8 is 2, because 2 * 2 * 2 equals 8. Understanding cube roots is crucial when working with inverse functions, like in our exercise.
In the formula \( \sqrt[3]{x+5} \), the \( \sqrt[3]{} \) operation is used to undo the cubing process. It's the counterpart to raising a number to the power of three and is what helps restore the original input variable \( x \).
To find a cube root, remember:
  • The cube root operation is the inverse of cubing.
  • If \( x = a^3 \), then \( a = \sqrt[3]{x} \).
  • Cube roots apply to both positive and negative numbers; for instance, \( \sqrt[3]{-8} = -2 \).
Getting comfortable with cube roots helps simplify and solve equations when dealing with inverse functions.
Function Composition
Function composition involves applying one function to the results of another. It's like putting one operation inside another operation.
For example, if you have a function \( f(x) \) and another function \( g(x) \), the composition \( f(g(x)) \) means you take \( g(x) \) and plug it into \( f(x) \). This results in a new function.
Understanding composition helps confirm inverse functions are correctly identified. When \( f(f^{-1}(x)) = x \), it shows that applying \( f \) to \( f^{-1}(x) \) gives you back the original \( x \).
For instance in our case:
  • Composition confirmed using \( f(f^{-1}(x)) = (\sqrt[3]{x+5})^3 - 5 \).
  • After simplifying, it equals \( x \), verifying the inverse works just as expected.
Function compositions ensure that the operations inversely mirror each other correctly, turning expressions back to the original inputs.
Solving Equations
Solving equations is about finding the value of a variable that makes the equation true. This process is key in finding inverse functions, where the goal is to rewrite the given expression to solve for the input variable.
In our example:
  • We started with \( y = x^3 - 5 \).
  • The task was to solve for \( x \), which involved rearranging to get \( x^3 \) on one side: \( y + 5 = x^3 \).
  • Finally, taking the cube root of both sides, we solved for \( x \) and found the inverse: \( x = \sqrt[3]{y + 5} \).
Equations can sometimes be intimidating, but by rearranging terms and methodically progressing through the operations, solving them becomes a manageable task.
Always remember to perform the same operation on both sides to maintain balance and correctness in the equation.

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Most popular questions from this chapter

Psychologists call the graph of the formula \(t=\frac{1}{c} \ln \left(\frac{A}{A-N}\right)\) the learning curve, since the formula relates time \(t\) passed, in weeks, to a measure N of learning achieved, to a measure A of maximum learning possible, and to a measure \(c\) of an individual's learning style. Round to the nearest week. Norman is learning to type. If he wants to type at a rate of 50 words per minute \((N \text { is } 50)\) and his expected maximum rate is 75 words per minute \((A \text { is } 75)\), find how many weeks it should take him to achieve his goal. Assume that \(c\) is 0.09

Solve each system of equations. See Section 4.1. $$ \left\\{\begin{array}{c} {5 x+y=5} \\ {-3 x-2 y=-10} \end{array}\right. $$

Graph each function by finding ordered pair solutions, plotting the solutions, and then drawing a smooth curve through the plotted points. $$ f(x)=e^{x+4} $$

The formula \(y=y_{0} e^{k t}\) gives the population size \(y\) of a population that experiences an annual rate of population growth \(k\) (given as a decimal. In this formula, \(t\) is time in years and \(y_{0}\) is the initial population at time \(0 .\) Use this formula to solve Exercises 69 and 70. In 2010 , the population of Michigan was approximately \(9,939,000\) and decreasing according to the formula \(y=y_{0} e^{-0.003 t} .\) Assume that the population continues to decrease according to the given formula and predict how many years after which the population of Michigan will be \(9.500,000 .\) (Hint: Let \(y_{0}=9,939,000 ; y=9,500,000,\) and solve for \(t .\) (Source: U.S. Bureau of the Census)

Find the value of each logarithmic expression. See Examples 3 and 5. $$ \log _{3} 9 $$

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