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Use a calculator to approximate each logarithm to four decimal places. See Examples I and 5. \(\ln 2\)

Short Answer

Expert verified
The approximate value of \( \ln(2) \) is 0.6931.

Step by step solution

01

Understand the Natural Logarithm Function

The natural logarithm, denoted as \( \ln(x) \), is the logarithm to the base \( e \), where \( e \) is an irrational constant approximately equal to 2.718281828. Calculating \( \ln(2) \) means finding the exponent to which \( e \) must be raised to yield 2.
02

Input the Value into Calculator

Use a scientific calculator or a calculator app that has the natural logarithm function. Find the "ln" button, which represents the natural logarithm, and press it.
03

Calculate \( \ln(2) \)

While pressing the "ln" button, enter the number 2. This calculates the natural logarithm of 2.
04

Record the Result

After entering 2 and pressing "ln", the calculator should display the result. The output is an approximation of \( \ln(2) \) to four decimal places.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

logarithm approximation
When dealing with logarithm approximation, the goal is to find a close value of a logarithm rather than an exact one. Here, we are particularly interested in the natural logarithm, which uses the base of the mathematical constant \( e \). Approximating \( \ln(2) \) involves determining the power to which \( e \) (approximately 2.71828) must be raised to obtain the number 2.

Since the value of \( \ln(2) \) is not an integer, a scientific calculator is needed to provide an approximation to four decimal places. Logarithm approximation becomes essential in various mathematical applications where approximating complex expressions simplifies analysis and understanding.

Understanding this concept helps with many real-world problems, such as calculating growth rates, decibel levels, and more, especially when precise values are not necessary or feasible to calculate.
scientific calculator
A scientific calculator is a specialized electronic device capable of performing complex mathematical operations, including logarithmic functions. For students tasked with approximating logarithms like \( \ln(2) \), a scientific calculator is essential. Here’s how you can use it:
  • Locate the "ln" button, which stands for the natural logarithm.
  • Enter the number you wish to find the logarithm of, in this case, 2.
  • Press the "ln" button to calculate and display the result.

Scientific calculators not only compute natural logs but also handle various other functions like trigonometry, powers, and decimals, making them invaluable for students in higher-level math courses.

In today's tech-savvy world, these devices are also available as apps on smartphones and computers, ensuring students can access this powerful tool anytime they need it.
exponential functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. One of the most crucial bases in mathematics is \( e \), widely used in natural exponential functions. Understanding these functions is critical because they describe many natural phenomena such as population growth and radioactive decay.

The natural logarithm, \( \ln(x) \), is closely related to exponential functions because it effectively reverses the exponentiation by \( e \). If you take the natural logarithm of an exponential expression, it undoes the exponentiation, taking you back to the original exponent.
  • For example, if \( \ln(e^x) = x \), then \( e^{\ln(x)} = x \).
  • This relationship showcases how logarithms can simplify the process of solving equations involving exponential growth or decay.

Thus, exponential functions and their inverses in the form of logarithms play a foundational role in calculus and advanced math, enhancing a student's ability to solve wide-ranging practical problems.

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Most popular questions from this chapter

Psychologists call the graph of the formula \(t=\frac{1}{c} \ln \left(\frac{A}{A-N}\right)\) the learning curve, since the formula relates time \(t\) passed, in weeks, to a measure N of learning achieved, to a measure A of maximum learning possible, and to a measure \(c\) of an individual's learning style. Round to the nearest week. Janine is working on her dictation skills. She wants to take dictation at a rate of 150 words per minute and believes that the maximum rate she can hope for is 210 words per minute. Find how many weeks it should take her to achieve the 150 words per minute level if \(c\) is 0.07

Write each as a logarithmic equation. See Example 2. $$ 10^{-2}=\frac{1}{100} $$

The formula \(y=y_{0} e^{k t}\) gives the population size \(y\) of a population that experiences an annual rate of population growth \(k\) (given as a decimal. In this formula, \(t\) is time in years and \(y_{0}\) is the initial population at time \(0 .\) Use this formula to solve Exercises 69 and 70. In 2010 , the population of Michigan was approximately \(9,939,000\) and decreasing according to the formula \(y=y_{0} e^{-0.003 t} .\) Assume that the population continues to decrease according to the given formula and predict how many years after which the population of Michigan will be \(9.500,000 .\) (Hint: Let \(y_{0}=9,939,000 ; y=9,500,000,\) and solve for \(t .\) (Source: U.S. Bureau of the Census)

Psychologists call the graph of the formula \(t=\frac{1}{c} \ln \left(\frac{A}{A-N}\right)\) the learning curve, since the formula relates time \(t\) passed, in weeks, to a measure N of learning achieved, to a measure A of maximum learning possible, and to a measure \(c\) of an individual's learning style. Round to the nearest week. A psychologist is measuring human capability to memorize nonsense syllables. Find how many weeks it should take a subject to learn 15 nonsense syllables if the maximum pos. sible to learn is 24 syllables and \(c\) is 0.17 .

Use a graphing calculator to solve each equation. For example, to solve Exercise \(73,\) let \(Y_{1}=e^{0.3 x}\) and \(Y_{2}=8\) and graph the equations The \(x\) -value of the point of intersection is the solution. Round all solutions to two decimal places. $$ e^{0.3 x}=8 $$

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