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Find the exact value. See Examples 2 and \(6 .\). \(\ln e^{2}\)

Short Answer

Expert verified
The exact value is 2.

Step by step solution

01

Understand the Problem Statement

We need to find the exact value of the expression \( \ln e^{2} \). This represents the natural logarithm (ln) of \( e^{2} \), where \( e \) is the base of natural logarithms (approximately 2.718).
02

Apply the Logarithmic Identity

Recall the identity \( \ln(e^x) = x \) for any real number \( x \). In this case, \( x = 2 \). This identity holds because the natural logarithm is the inverse function of the exponential function \( e^x \).
03

Calculate the Expression

Using the identity from Step 2, substitute \( x = 2 \): \( \ln(e^2) = 2 \). Thus, the exact value of \( \ln e^{2} \) is \( 2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are fundamental in mathematics, as they describe a relationship where the rate of change of a quantity is proportional to its current value. The most famous base for these functions is Euler's number, denoted as \( e \), approximately equal to 2.718. This special number is the foundation of natural exponentiation functions like \( e^x \). Exponential functions can be expressed generally as \( f(x) = a \, b^x \), where:
  • \( a \) is a constant that represents the initial value.
  • \( b \) is the base of the exponential, which determines the growth rate.
  • \( x \) is the exponent.
These functions grow faster than any polynomial function, making them useful for modeling rapid growth, such as populations or investments. The function \( e^x \) is unique because its rate of change at any point is equal to the function's value, i.e., the derivative of \( e^x \) is \( e^x \), which is a property that distinguishes it among exponentials.
Logarithmic Identities
Logarithmic identities are rules that simplify solving logarithms, enabling more straightforward manipulation of expressions. A key identity to remember is that the logarithm is the inverse operation of exponentiation. This means applying a logarithm can reverse the effect of exponential functions. A particular identity is \( \ln(e^x) = x \), which was used in the original exercise.This specific identity \( \ln(e^x) = x \) can be understood using basic properties:
  • \( \ln \) denotes the natural logarithm, using the base \( e \).
  • The expression \( e^x \) suggests applying an exponential function on \( x \).
  • Applying \( \ln \) on \( e^x \) cancels each other out because they are inverse operations.
Understanding these identities is crucial for simplifying complex equations and for finding solutions more efficiently, as demonstrated in calculating \( \ln(e^2) = 2 \).
Inverse Functions
Inverse functions reverse the effects of their respective functions. If you have a function \( f(x) \), its inverse, usually denoted as \( f^{-1}(x) \), operates such that applying \( f \) followed by \( f^{-1} \) returns the original input, i.e., \( f(f^{-1}(x)) = x \). In the case of exponential and logarithmic functions, they are inverses of each other. This property is fundamental:
  • The exponential function \( e^x \) raises the base \( e \) to the power of \( x \).
  • The natural logarithm \( \ln(x) \) gives you the power to which \( e \) must be raised to get \( x \).
This relationship is key when evaluating expressions like \( \ln(e^x) \). Since they are inverse functions, applying both results in the exponent \( x \), reinforcing that understanding inverse functions clarifies operations with logarithms and exponentials.

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