/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Solve each polynomial inequality... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each polynomial inequality. Write the solution set in interval notation. $$ (x-6)(x-4)(x-2)>0 $$

Short Answer

Expert verified
The solution set is \((2, 4) \cup (6, \infty)\).

Step by step solution

01

Identify the Zero Points

First, identify the zero points of the inequality by setting each factor equal to zero. For the inequality \((x-6)(x-4)(x-2)>0\), the zero points are found by solving:\[ x-6 = 0 \Rightarrow x=6 \]\[ x-4 = 0 \Rightarrow x=4 \]\[ x-2 = 0 \Rightarrow x=2 \]
02

Create a Number Line Chart

Place the zero points 2, 4, and 6 on a number line to divide it into intervals. The intervals created are: 1. \((-\infty, 2)\)2. \((2, 4)\)3. \((4, 6)\)4. \((6, \infty)\)
03

Test the Intervals

Select a test point from each interval and substitute it into the inequality \((x-6)(x-4)(x-2)>0\) to determine whether the product in each interval is positive or negative. - For \((-\infty, 2)\), use \(x=0\): \((0-6)(0-4)(0-2) = -48\) (negative)- For \((2, 4)\), use \(x=3\): \((3-6)(3-4)(3-2) = 3\) (positive)- For \((4, 6)\), use \(x=5\): \((5-6)(5-4)(5-2) = -3\) (negative)- For \((6, \infty)\), use \(x=7\): \((7-6)(7-4)(7-2) = 9\) (positive)
04

Identify Solution Intervals

We are looking for where the expression is greater than zero (positive). Based on the test points:- \( (2, 4) \) is positive- \( (6, \infty) \) is positiveThus, the solution set where \((x-6)(x-4)(x-2)>0\) is in the intervals \((2, 4) \cup (6, \infty)\).
05

Write the Solution Set in Interval Notation

The solution set in interval notation, excluding the points where the product is zero, is:\( (2, 4) \cup (6, \infty) \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interval Notation
Interval notation is a way to represent the set of solutions to inequalities using intervals on the real number line. This method succinctly describes the continuous range of values, which can be seen as segments or variations where a particular condition holds true. Let's break down its components:

1. **Parentheses \((\) and \()\):** These indicate that the endpoint is not included in the interval. For example, \((2,4)\) means that the values between 2 and 4 are included, but neither 2 nor 4 are part of the solution set.
2. **Brackets \([\) and \()]\):** These symbols show that the endpoint is part of the interval. For instance, \([2,4]\) would mean both 2 and 4, as well as all numbers in between, are included.

Using interval notation helps to capture the idea of solutions over continuous segments rather than listing individual numbers one by one. In the exercise, the solution \((2, 4) \cup (6, \infty)\) translates to having solutions that lie between 2 and 4 and again from 6 to infinity, excluding the endpoints themselves.
Zero Points
Zero points, also known as roots or solutions to an equation, are the values where the polynomial equation equals zero. Finding these points is crucial when solving polynomial inequalities, as they help set the boundaries for testing intervals.

To find the zero points of a polynomial inequality like \((x-6)(x-4)(x-2)>0\), you set each polynomial factor equal to zero and solve for \(x\):
  • \(x-6=0\) yields \(x=6\)
  • \(x-4=0\) yields \(x=4\)
  • \(x-2=0\) yields \(x=2\)
These zero points \(2, 4,\) and \(6\) divide the number line into different intervals, which become essential in checking where the inequality truly holds. Knowing these roots allows you to determine the regions around them where the inequality switches from true to false or vice versa.
Number Line Method
The number line method is a visual way to solve polynomial inequalities by analyzing various intervals that arise from the zero points. A number line helps to present these intervals clearly and decide which parts satisfy the given inequality.

To use this method, first mark the zero points on the number line, which divides the number line into distinct intervals. For the inequality \((x-6)(x-4)(x-2)>0\), the number line splits into parts: \((-fty, 2)\), \((2, 4)\), \((4, 6)\), and \((6, fty)\).

After marking the zero points, select a test point from within each interval and substitute back into the inequality to see if the result is positive or negative.
  • If positive, it meets the inequality \((x-6)(x-4)(x-2)>0\).
  • If negative, it does not satisfy the inequality.
Using the number line method makes it easier to visualize the problem and categorize regions of solutions effectively.
Solution Intervals
Solution intervals are the sections of the number line where the inequality holds true. They signify the ranges where the polynomial, after factoring and evaluating through test points, meets the criteria of the inequality.

In practice, once you identify the nature (positive or negative) of each interval derived from the number line, you select those intervals where the inequality is satisfied. In our example, considering the inequality \((x-6)(x-4)(x-2)>0\), the test points revealed the following:
  • The calculations for \((2, 4)\) resulted in a positive value, indicating this interval satisfies the inequality.
  • The calculations for \((6, fty)\) also resulted in a positive value, meaning it meets the criteria of the inequality as well.
The solution intervals are then expressed in interval notation as \((2, 4) \cup (6, fty)\), showcasing the unified solution by combining overlapping or disjoint intervals that satisfy the inequality.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Simplify each expression. See Section 7.1 $$ \frac{1}{2}-\sqrt{\frac{9}{4}} $$

Sketch the graph of each function. See Section 8.5. $$ f(x)=x^{2}+2 $$

Neglecting air resistance, the distance \(s(t)\) in feet traveled by a freely falling object is given by the function \(s(t)=16 t^{2},\) where \(t\) is time in seconds. Use this formula to solve Exercises 79 through \(82 .\) Round answers to two decimal places. The Burj Khalifa, the tallest building in the world, was completed in 2010 in Dubai. It is estimated to be 2717 feet tall. How long would it take an object to fall to the ground from the top of the building? (Source: Council on Tall Buildings and Urban Habitat)

Without calculating, tell whether each graph has a minimum value or a maximum value. See the Concept Check in the section. $$ G(x)=3-\frac{1}{2} x+0.8 x^{2} $$

Find the maximum or minimum value of each function. Approxi- mate to two decimal places. The projected number of Wi-Fi-enabled cell phones in the United States can be modeled by the quadratic function \(c(x)=-0.4 x^{2}+21 x+35,\) where \(c(x)\) is the projected number of Wi-Fi-enabled cell phones in millions and \(x\) is the number of years after \(2009 .\) (Source: Techcrunchies.com) A. Will this function have a maximum or a minimum? How can you tell? B. According to this model, in what year will the number of Wi-Fi-enabled cell phones in the United States be at its maximum or minimum? C. What is the maximum/minimum number of Wi-Fienabled cell phones predicted? Round to the nearest whole million.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.