Chapter 8: Problem 80
Use the quadratic formula and a calculator to approximate each solution to the nearest tenth. \(3.6 x^{2}+1.8 x-4.3=0\)
Short Answer
Expert verified
Solutions: \( x \approx 0.9 \) and \( x \approx -1.4 \).
Step by step solution
01
Identify the coefficients
In the quadratic equation \( ax^2 + bx + c = 0 \), identify the coefficients: \( a = 3.6 \), \( b = 1.8 \), \( c = -4.3 \).
02
Write the quadratic formula
The quadratic formula is \( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \). We will use this formula to solve for \( x \).
03
Calculate the discriminant
The discriminant in the quadratic formula is \( b^2 - 4ac \). Substitute the values: \( 1.8^2 - 4(3.6)(-4.3) \).
04
Evaluate the discriminant
Calculate \( 1.8^2 = 3.24 \) and \( 4 \times 3.6 \times -4.3 = -61.92 \). Thus, \( 1.8^2 - 4 \times 3.6 \times (-4.3) = 3.24 + 61.92 = 65.16 \).
05
Calculate the square root of the discriminant
Take the square root of the discriminant: \( \sqrt{65.16} \approx 8.08 \).
06
Solve for the two possible values of x
Substitute the values into the quadratic formula: \( x = \frac{{-1.8 \pm 8.08}}{7.2} \). Compute the two cases for \( x \):1. \( x = \frac{{-1.8 + 8.08}}{7.2} \)2. \( x = \frac{{-1.8 - 8.08}}{7.2} \).
07
Approximate each solution
Calculate each case:1. \( x = \frac{{6.28}}{7.2} \approx 0.9 \)2. \( x = \frac{{-9.88}}{7.2} \approx -1.4 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
The discriminant is a crucial part of the quadratic formula, helping determine the nature and number of solutions for a given quadratic equation. It is represented by the expression within the square root sign: \( b^2 - 4ac \), where \( a \), \( b \), and \( c \) are coefficients from the standard quadratic equation format \( ax^2 + bx + c = 0 \).
The value of the discriminant can tell us much about the equation:
The value of the discriminant can tell us much about the equation:
- If the discriminant is positive, there are two distinct real solutions.
- If it is zero, there's exactly one real solution, also known as a repeated or double root.
- If negative, it indicates there are no real solutions, but rather two complex solutions.
Quadratic Equation
A quadratic equation is a polynomial equation in the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). It is called "quadratic" because "quad" means square, referring to the \( x^2 \) term.
Quadratic equations are fundamental in mathematics, frequently appearing in various applications like physics, engineering, and economics. Solving them involves finding the values of \( x \) that satisfy the equation. These values are also referred to as the "roots" of the equation.
In the given problem, the equation is \( 3.6x^2 + 1.8x - 4.3 = 0 \). Identifying the coefficients correctly is the first step:
Quadratic equations are fundamental in mathematics, frequently appearing in various applications like physics, engineering, and economics. Solving them involves finding the values of \( x \) that satisfy the equation. These values are also referred to as the "roots" of the equation.
In the given problem, the equation is \( 3.6x^2 + 1.8x - 4.3 = 0 \). Identifying the coefficients correctly is the first step:
- \( a = 3.6 \)
- \( b = 1.8 \)
- \( c = -4.3 \)
Solving Quadratic Equations
To solve quadratic equations, one powerful tool is the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). This formula allows you to find solutions for any quadratic equation. Just plug in the coefficients \( a \), \( b \), and \( c \) into the formula, and evaluate accordingly.
The "\( \pm \)" symbol indicates there are generally two potential solutions since you will solve the equation once considering "\( + \sqrt{b^2 - 4ac} \)" and once with "\( - \sqrt{b^2 - 4ac} \)".
In our task, we substitute:
The "\( \pm \)" symbol indicates there are generally two potential solutions since you will solve the equation once considering "\( + \sqrt{b^2 - 4ac} \)" and once with "\( - \sqrt{b^2 - 4ac} \)".
In our task, we substitute:
- \( b = 1.8 \)
- \( a = 3.6 \)
- \( c = -4.3 \)
- First calculate the discriminant \( b^2 - 4ac \) as previously discussed to be \( 65.16 \).
- Then find the square root of the discriminant: \( \sqrt{65.16} \approx 8.08 \).
- Substitute back into the quadratic formula: \[ x = \frac{-1.8 \pm 8.08}{7.2} \].
Approximate Solutions
In many cases, especially in real-world problems, solutions may not be perfect integers or simple fractions. Hence, approximating to a desirable level of precision becomes necessary. To approximate solutions using the quadratic formula, utilize a calculator for values like square roots and divisions to get decimal results.
From our solutions:
From our solutions:
- The first root is \( x = \frac{-1.8 + 8.08}{7.2} \approx 0.9 \).
- The second root is \( x = \frac{-1.8 - 8.08}{7.2} \approx -1.4 \).