Chapter 8: Problem 38
Find the vertex of the graph of each quadratic function. Determine whether the graph opens upward or downward, find any intercepts, and sketch the graph. See Examples 1 through 4 . $$ f(x)=3 x^{2}+12 x+16 $$
Short Answer
Expert verified
Vertex is (-2, 4). Parabola opens upward with y-intercept at (0, 16) and no real x-intercepts.
Step by step solution
01
Identify the Coefficients
The given quadratic function is \( f(x) = 3x^2 + 12x + 16 \). The standard form of a quadratic function is \( ax^2 + bx + c \). Here, \(a = 3\), \(b = 12\), and \(c = 16\).
02
Determine the Direction the Parabola Opens
The sign of coefficient \(a\) determines the opening direction. Since \(a = 3\) is positive, the parabola opens upward.
03
Find the Vertex using the Vertex Formula
The vertex \((h, k)\) of a parabola given by \(f(x) = ax^2 + bx + c\) is found using \(h = -\frac{b}{2a}\) and \(k = f(h)\). Calculate \(h\): \(-\frac{b}{2a} = -\frac{12}{2(3)} = -2\). Substitute \(x = -2\) into \(f(x)\) to find \(k\): \(f(-2) = 3(-2)^2 + 12(-2) + 16 = 12 - 24 + 16 = 4\). Thus, the vertex is \((-2, 4)\).
04
Find the Intercepts
To find the y-intercept, substitute \(x = 0\) into \(f(x)\): \(f(0) = 16\), so the y-intercept is \((0, 16)\). For x-intercepts, solve \(3x^2 + 12x + 16 = 0\) using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Here, \(x = \frac{-12 \pm \sqrt{144 - 192}}{6} = \frac{-12 \pm \sqrt{-48}}{6} \). Since the discriminant is negative, there are no real x-intercepts.
05
Sketch the Graph
Plot the vertex \((-2, 4)\) and the y-intercept \((0, 16)\) on the graph. Since the parabola opens upward and there are no real x-intercepts, it will be above the x-axis. Draw a smooth curve through these points, reflecting the symmetry around the vertex.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a key point located on the graph of a quadratic function. It serves as the peak or the lowest point, depending on the parabola's direction. Given a quadratic function in the standard form \(f(x) = ax^2 + bx + c\), we can find the vertex using the vertex formula. This formula is especially useful as it allows us to determine both the x and y coordinates of the vertex. For the x-coordinate, also known as \(h\), use the formula \(h = -\frac{b}{2a}\). Once we have \(h\), finding the y-coordinate, \(k\), is as simple as substituting \(x = h\) back into the original quadratic equation, \(f(h)\). To illustrate, given the quadratic \(f(x) = 3x^2 + 12x + 16\), we calculated \(h = -2\) and found \(k = 4\), meaning the vertex is \((-2, 4)\). Vertices are important as they help in sketching the parabola and understanding its symmetry.
Parabola Direction
The direction in which a parabola opens is crucial in understanding the shape of the graph of a quadratic function. This direction is dictated solely by the sign of the coefficient \(a\) in the quadratic expression \(f(x) = ax^2 + bx + c\).
- If \(a > 0\), the parabola opens upward, forming a U-shape.
- If \(a < 0\), the parabola opens downward, forming an upside-down U-shape.
Quadratic Formula
The quadratic formula is a powerful tool used to find the roots of a quadratic equation, which are the x-intercepts of the graph. It is expressed as: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] This formula can always be applied to any quadratic equation of the form \(ax^2 + bx + c = 0\). While the nature of the roots (real or complex) is determined by the discriminant, \(b^2 - 4ac\):
- If the discriminant is positive, the equation has two distinct real roots.
- If it equals zero, there is exactly one real root.
- A negative discriminant indicates there are no real roots, only complex ones.
Intercepts of a Graph
Intercepts are the points where a graph crosses the x-axis and y-axis. They provide insight into where the changes happen in a quadratic graph.
- The y-intercept is found by evaluating the function at \(x = 0\). For \(f(x) = 3x^2 + 12x + 16\), substituting \(x = 0\) gives \(f(0) = 16\), so the y-intercept is \((0, 16)\).
- The x-intercepts are determined by solving the equation \(ax^2 + bx + c = 0\) using methods like factoring or the quadratic formula. If there are no real solutions (as in our case where we encountered a negative discriminant), it indicates that the graph doesn't touch the x-axis.