Chapter 8: Problem 20
Use the square root property to solve each equation. See Examples I through 4. $$ 3 p^{2}+36=0 $$
Short Answer
Expert verified
The solutions are \(p = \pm 2i\sqrt{3}\).
Step by step solution
01
Simplify the equation
Start by isolating the term with the square. Here, subtract 36 from both sides to get the isolated square term:\[3p^2 = -36\]
02
Divide to isolate the square
Next, divide both sides of the equation by 3 to solve for \(p^2\):\[p^2 = -12\]
03
Apply the square root property
Use the square root property, which states that if \(a^2 = b\), then \(a = \pm \sqrt{b}\). Apply this to find \(p\):\[p = \pm \sqrt{-12}\]
04
Simplify the square root of a negative number
Simplify \(\sqrt{-12}\) by breaking it down:\(\sqrt{-12} = \sqrt{-1} \times \sqrt{12}\).Since \(\sqrt{-1} = i\), we have:\[p = \pm i\sqrt{12}\]
05
Simplify further
Simplify \(\sqrt{12}\) to get its simplest form:\[\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}\]Thus, we can express \(p\) as:\[p = \pm 2i\sqrt{3}\]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are numbers that consist of a real part and an imaginary part. The imaginary part of a complex number is expressed using the imaginary unit denoted as "i," which is defined by the property that \(i^2 = -1\). This allows us to extend the real number system to include solutions to equations that involve square roots of negative numbers. For example:
\( \sqrt{-1} = i \),
\( \sqrt{-4} = 2i \),
\( \sqrt{-12} = \sqrt{-1} \times \sqrt{12} = i \sqrt{12} \).
So, complex numbers are extremely useful when you encounter an equation like \( p^2 = -12 \). Here, we use the square root property to introduce the imaginary number, allowing us to express the roots as \( p = \pm i\sqrt{12} \). By using complex numbers, we can solve otherwise difficult equations and delve into realms extending beyond just real numbers.
\( \sqrt{-1} = i \),
\( \sqrt{-4} = 2i \),
\( \sqrt{-12} = \sqrt{-1} \times \sqrt{12} = i \sqrt{12} \).
So, complex numbers are extremely useful when you encounter an equation like \( p^2 = -12 \). Here, we use the square root property to introduce the imaginary number, allowing us to express the roots as \( p = \pm i\sqrt{12} \). By using complex numbers, we can solve otherwise difficult equations and delve into realms extending beyond just real numbers.
Equation Solving
When solving equations involving squares, such as \(3p^2 + 36 = 0\), one often uses the square root property to find solutions. The square root property tells us that if \(a^2 = b\), then \(a = \pm \sqrt{b}\). Here's how it applies:
This sequence of steps systematically breaks down the equation into manageable parts, allowing even seemingly daunting problems like \(p^2 = -12\) to be solved using structured logical steps. This logical flow in equation solving helps when handling equations that involve both real and complex solutions.
- First, isolate the term with the square (\(p^2\)) by performing operations like subtraction or addition on both sides of the equation.
- Divide through by any coefficient that multiplies the squared term to isolate it completely.
- Apply the square root property to solve for the unknown variable.
This sequence of steps systematically breaks down the equation into manageable parts, allowing even seemingly daunting problems like \(p^2 = -12\) to be solved using structured logical steps. This logical flow in equation solving helps when handling equations that involve both real and complex solutions.
Simplifying Radicals
Simplifying radicals is a crucial step in making expressions easier to understand and compute. A radical expression can often be broken down into simpler components to reveal its base structure. Here's the process using \(\sqrt{12}\) as an example:
Applying this simplification to \(\sqrt{-12}\), we insert the imaginary unit as part of our simplification, so \(\sqrt{-12} = i\sqrt{12} = 2i\sqrt{3}\).
Through simplifying radicals, you not only tidy up expressions but also prepare them for further operations or to identify properties such as whether they represent complex numbers.
- First, identify the factors of the number under the square root. For 12, it's 4 and 3 (since \(12 = 4 \times 3\)).
- Next, simplify \(\sqrt{4 \times 3}\) by separating it into \(\sqrt{4} \times \sqrt{3}\).
- Calculate each of these simpler square roots. \(\sqrt{4} = 2\), so \(\sqrt{4} \times \sqrt{3} = 2\sqrt{3}\).
Applying this simplification to \(\sqrt{-12}\), we insert the imaginary unit as part of our simplification, so \(\sqrt{-12} = i\sqrt{12} = 2i\sqrt{3}\).
Through simplifying radicals, you not only tidy up expressions but also prepare them for further operations or to identify properties such as whether they represent complex numbers.