Chapter 7: Problem 73
Perform each indicated operation. Write the result in the form \(a+b i\). $$ \frac{2-3 i}{2+i} $$
Short Answer
Expert verified
The result is \(\frac{1}{5} - \frac{8}{5}i\).
Step by step solution
01
Identify the Complex Conjugate
To simplify the fraction \(\frac{2-3i}{2+i}\), we need to multiply the numerator and the denominator by the complex conjugate of the denominator, which is \(2-i\).
02
Multiply the Numerator and Denominator
Multiply both the numerator (\(2-3i\)) and the denominator (\(2+i\)) by the complex conjugate \(2-i\): \[\frac{(2-3i)(2-i)}{(2+i)(2-i)}\].
03
Simplify the Numerator
Expand \((2-3i)(2-i)\): Apply the distributive property:\[2 \cdot 2 + 2 \cdot (-i) - 3i \cdot 2 - 3i \cdot (-i)\] Calculate the terms: = \(4 - 2i - 6i + 3i^2\). Since \(i^2 = -1\), this becomes: \(4 - 8i + 3(-1) = 4 - 8i - 3\)= \(1 - 8i\).
04
Simplify the Denominator
Expand \((2+i)(2-i)\): Using the difference of squares formula: \[2^2 - (i)^2 = 4 - (-1) = 4 + 1 = 5\].
05
Write the Result in Simplified Form
The fraction simplifies to:\[\frac{1-8i}{5}\]We can express it in the form \(a + bi\) by dividing each term by 5: \[\frac{1}{5} - \frac{8}{5}i\].So, the final result is \(\frac{1}{5} - \frac{8}{5}i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Complex Conjugate
Complex numbers have both a real part and an imaginary part. A complex conjugate is a unique way of transforming a complex number to help in simplifying various expressions. When a complex number is written as \( a+bi \), its complex conjugate is written as \( a-bi \). The complex conjugate essentially flips the sign of the imaginary part, leaving the real part unchanged. For example, the complex conjugate of \(2+i\) is \(2-i\). Using complex conjugates is especially useful in division, as they help eliminate the imaginary part in the denominator. To multiply a complex number by its conjugate, you obtain a purely real number. This is achieved because the imaginary components cancel out, and the result is based on the formula \((a+b)(a-b) = a^2 - b^2\), which exploits the properties of squared terms.
Mastering Multiplying Complex Numbers
When it comes to multiplying complex numbers, the distributive property is your go-to method. Consider two complex numbers: \((2-3i)\) and \((2-i)\). To multiply them, distribute each term in the first complex number across each term in the second.
- First, multiply the real parts: \(2 \times 2 = 4\)
- Next, take the real part times the imaginary part: \(2 \times (-i) = -2i\)
- Then, multiply the imaginary part times the real part: \(-3i \times 2 = -6i\)
- Finally, multiply the imaginary parts: \(-3i \times (-i) = 3i^2\)
Simplifying Complex Fractions
Complex fractions might initially look complicated, but with the right approach, they become manageable. The key is unraveling the fraction into a form where complex numbers appear as separate terms \(a + bi\). In our example, \(\frac{1-8i}{5}\), each of these terms can be further simplified by dividing through the denominator separately:
- The real component is \(\frac{1}{5}\)
- The imaginary component is \(\frac{-8}{5}i\)