Chapter 6: Problem 7
Divide. $$ \left(x^{2}+3 x+2\right) \div(x+2) $$
Short Answer
Expert verified
The quotient is \(x + 1\).
Step by step solution
01
Setup the Division
Write the polynomial equation as a long division: \Dividend (inside): \(x^2 + 3x + 2\) \Divider (outside): \(x + 2\). We will divide the first term of the dividend by the first term of the divider.
02
Divide the Leading Terms
Divide the first term of the polynomial, \(x^2\), by the first term of the divisor, \(x\). This gives \(x\). This is the first term of our quotient.
03
Multiply and Subtract
Multiply \(x\) by \(x + 2\) to get \(x^2 + 2x\). Subtract \(x^2 + 2x\) from the dividend \(x^2 + 3x + 2\), which results in \(x + 2\).
04
Repeat Division
Now, divide the new dividend \(x + 2\) by \(x\). This gives \(+1\). This is the next term in our quotient.
05
Multiply and Subtract Again
Multiply the new quotient term \(+1\) by the divisor \(x + 2\), resulting in \(x + 2\). Subtract \(x + 2\) from \(x + 2\), yielding a remainder of 0.
06
Compile the Solution
Since there is no remainder, the complete quotient is \(x + 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Algebraic Long Division
When working with polynomial long division, we use a process much like the long division method for numbers. This technique is often referred to as algebraic long division. It's a way of simplifying complex polynomials by dividing one polynomial by another.
To begin, set up the division much like you would with numbers:
Repeat the process using the result of the subtraction as your new dividend. Continue until you reach a remainder smaller than the divisor or zero, indicating that you've completed the division.
To begin, set up the division much like you would with numbers:
- Place the dividend, the polynomial you are dividing, under the division bracket.
- Write the divisor, the polynomial you're dividing by, outside the bracket.
Repeat the process using the result of the subtraction as your new dividend. Continue until you reach a remainder smaller than the divisor or zero, indicating that you've completed the division.
Polynomials
Polynomials are mathematical expressions that consist of variables and coefficients. They are a sum of terms, each term including a variable raised to an exponent and multiplied by a coefficient. The degree of a polynomial is the highest exponent of its variable.
Consider the polynomial from our exercise: \(x^2 + 3x + 2\). This expression has three terms:
Consider the polynomial from our exercise: \(x^2 + 3x + 2\). This expression has three terms:
- \(x^2\) which is the quadratic term, having an exponent of 2.
- \(3x\) the linear term, with an exponent of 1. The coefficient here is 3.
- 2 the constant term, where the exponent of the variable is 0.
- A constant has a degree of 0 (e.g., 2).
- A linear polynomial has a degree of 1 (e.g., \(3x\)).
- A quadratic polynomial like \(x^2 + 3x + 2\) has a degree of 2.
Remainder Theorem
The Remainder Theorem offers a convenient method for evaluating the remainder in polynomial division. It states that when a polynomial \(f(x)\) is divided by \(x - a\), the remainder is simply \(f(a)\). This theorem can save you time, avoiding detailed division work.
In our exercise, once we obtain the quotient \(x + 1\) by dividing \(x^2 + 3x + 2\) by \(x + 2\), we discover a remainder of zero. This indicates that \(x + 2\) is a factor of the polynomial \(x^2 + 3x + 2\).
Applying the Remainder Theorem practically, if you wanted to find that same remainder without completing the algebraic division, evaluate the polynomial at the value that makes the divisor zero: \(x = -2\). Calculating \(f(-2)\) for \(x^2 + 3x + 2\) will give you 0, verifying that the remainder is indeed zero, consistent with our long division results too.
In our exercise, once we obtain the quotient \(x + 1\) by dividing \(x^2 + 3x + 2\) by \(x + 2\), we discover a remainder of zero. This indicates that \(x + 2\) is a factor of the polynomial \(x^2 + 3x + 2\).
Applying the Remainder Theorem practically, if you wanted to find that same remainder without completing the algebraic division, evaluate the polynomial at the value that makes the divisor zero: \(x = -2\). Calculating \(f(-2)\) for \(x^2 + 3x + 2\) will give you 0, verifying that the remainder is indeed zero, consistent with our long division results too.