/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Solve each equation. $$ \fra... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each equation. $$ \frac{x^{2}+6}{x}+5=\frac{2(x+3)}{x} $$

Short Answer

Expert verified
The solution to the equation is \(x = -3\).

Step by step solution

01

Simplifying Equation

First, note that both sides of the equation have a common denominator of \(x\). Multiply each term by \(x\) to eliminate the fractions: \[x^{2} + 6 + 5x = 2(x+3)\]
02

Expand and Simplify Terms

Distribute the 2 on the right side of the equation:\[x^{2} + 5x + 6 = 2x + 6\]
03

Rearrange to Form a Quadratic Equation

Move all terms to one side of the equation to form a standard quadratic equation:\[x^{2} + 5x + 6 - 2x - 6 = 0\]Simplify to combine like terms:\[x^{2} + 3x = 0\]
04

Factor the Quadratic Equation

Factor out the greatest common factor, \(x\):\[x(x + 3) = 0\]
05

Solve for the Roots

Set each factor equal to zero to find the solutions:1. \(x = 0\)2. \(x + 3 = 0\rightarrow x = -3\)
06

Check the Solutions

Check both solutions in the original equation to ensure they do not make any denominators zero:- For \(x = 0\): The original equation has division by zero, so it's not a valid solution.- For \(x = -3\): Substitute back to verify:\[\frac{(-3)^2 + 6}{-3} + 5 = \frac{2(-3+3)}{-3}\]The right side equals 0, and the left side simplifies as follows:\[\frac{9 + 6}{-3} + 5 = -5 + 5 = 0\]Therefore, \(x = -3\) is a valid solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring
Factoring is one of the key techniques used to solve quadratic equations. Essentially, it's about breaking down a complex expression into simpler, multipliable components. In this exercise, the quadratic equation we derived was \(x^2 + 3x = 0\). The process of factoring involves identifying common elements among the terms. Here, both terms share an \(x\), allowing us to factor it out. This gives us \(x(x + 3) = 0\). This factored form makes it easy to find the solutions or roots of the equation. It's like asking, "What numbers multiply to zero?" Since zero times anything is zero, we know either \(x = 0\) or \(x + 3 = 0\). Factoring is incredibly useful as it simplifies the equation to solvable parts and is often quicker than other methods.

When working with more complex quadratic equations, the skill of recognizing patterns is crucial. For instance, look for the difference of squares or perfect square trinomials as common structures to factor.
Checking Solutions
After finding potential solutions, it's critical to verify them. Checking solutions ensures they truly satisfy the original equation and don't introduce errors or undefined expressions like division by zero. In our exercise, we find potential solutions \(x = 0\) and \(x = -3\). We substitute these values back into the original equation to check if they create any problems.

For \(x = 0\), we find a division by zero, which means \(x = 0\) isn't valid. Checking \(x = -3\), we substitute it back in, confirming that both sides of the equation balance. By checking solutions, we confirm the validity of the answers and avoid unforeseen issues. Always remember – even if algebraically correct, substitute solutions to ensure they don’t lead to mathematical impossibilities like dividing by zero.
Common Denominator
In equations involving fractions, identifying a common denominator is a vital strategy to simplify. In this exercise, both fractions on the left and right sides of the equation shared a common denominator of \(x\). A common denominator allows us to eliminate the fraction by multiplying all terms by that denominator. This simplification step turns a fractional expression into something more straightforward.

Consider it like balancing different weights on a scale; having the same denominator allows each fraction to be directly compared and unified. Once everything is multiplied through by the common denominator, we can work with each expression fluidly as integers instead of fractions, which simplifies further algebraic manipulation.
Eliminating Fractions
Eliminating fractions is a crucial step to simplify equations and make them easier to handle. Fractions often complicate algebraic manipulation, so whenever possible, we aim to remove them by multiplying each term by the denominator. This cancels out the fractions, turning the equation into a more manageable form.

In our example, multiplying each term by \(x\) – the common denominator – got rid of the fractions, simplifying our equation to \(x^2 + 5x + 6 = 2x + 6\). This step is fundamental as it reduces the complexity, allowing us to treat each side of the equation more straightforwardly through addition, subtraction, multiplication, and factoring.

Remember, eliminating fractions may introduce potential solutions leading to undefined expressions, so always check your solutions in the context of the original equation. This protects against inadvertently accepting invalid solutions.

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Most popular questions from this chapter

Write an equation to describe each variation. Use k for the constant of proportionality. See Examples 1 through 7. \(y\) varies jointly as \(q, r,\) and \(t\)

Solve. See the Concept Check in this section. Choose the type of variation that each equation represents. a. Direct variation b. Inverse variation c. Joint variation $$ x y=\frac{2}{11} $$

Complete the following table for the inverse variation \(y=\frac{k}{x}\) over each given value of \(k .\) Plot the points on a rectangular coordinate system. $$ \begin{array}{|c|c|c|c|c|c|} \hline x & {\frac{1}{4}} & {\frac{1}{2}} & {1} & {2} & {4} \\ \hline y =\frac{k}{x} & {} & {} & {} & {} & {} \\ \hline \end{array} $$ $$ k=5 $$

Kraft Foods is a provider of many of the best-known food brands in our supermarkets. Among their wellknown brands are Kraft, Oscar Mayer, Maxwell House, and Oreo. Kraft Foods' annual revenues since 2005 can be modeled by the polynomial function \(R(x)=0.06 x^{3}+0.02 x^{2}+1.67 x+32.33,\) where \(R(x)\) is revenue in billions of dollars and \(x\) is the number of years since \(2005 .\) Kraft Foods' net profit can be modeled by the function \(P(x)=0.07 x^{3}-0.42 x^{2}+0.7 x+2.63,\) where \(P(x)\) is the net profit in billions of dollars and \(x\) is the number of years since \(2005 .\) (Source: Based on information from Kraft Foods) a. Suppose that a market analyst has found the model \(P(x)\) and another analyst at the same firm has found the model \(R(x) .\) The analysts have been asked by their manager to work together to find a model for Kraft Foods' profit margin. The analysts know that a company's profit margin is the ratio of its profit to its revenue. Describe how these two analysts could collaborate to find a function \(m(x)\) that models Kraft Foods' net profit margin based on the work they have done independently. b. Without actually finding \(m(x),\) give a general description of what you would expect the answer to be.

eBay is the leading online auction house. eBay's annual net profit can be modeled by the polynomial function \(P(x)=0.48 x^{3}+2.06 x^{2}+141 x+9.71,\) where \(P(x)\) is net profit in millions of dollars and \(x\) is the number of years since 2000 . eBay's annual revenue can be modeled by the function \(R(x)=1011 x-288,\) where \(R(x)\) is revenue in millions of dollars and \(x\) is years after 2000 . (Source: eBay, Inc., annual reports \(2000-2010\) ) a. Given that Net profit margin \(=\frac{\text { net profit }}{\text { revenue }}\) write a function, \(m(x),\) that models eBay's net profit margin. b. Use part (a) to predict eBay's profit margin in 2015 . Round to the nearest hundredth.

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