Chapter 5: Problem 73
If the cost, \(C(x),\) for manufacturing \(x\) units of a certain product is given by \(C(x)=x^{2}-15 x+50,\) find the number of units manufactured at a cost of \(\$ 9500 .\)
Short Answer
Expert verified
105 units are manufactured.
Step by step solution
01
Translate the Problem
We are given that the cost function is \(C(x) = x^2 - 15x + 50\). We need to find \(x\) such that \(C(x) = 9500\). The task is to solve the equation \(x^2 - 15x + 50 = 9500\) for \(x\).
02
Set Up the Equation
Set the cost function equal to 9500: \[ x^2 - 15x + 50 = 9500 \] Subtract 9500 from both sides to form a quadratic equation: \[ x^2 - 15x + 50 - 9500 = 0 \] Or simply: \[ x^2 - 15x - 9450 = 0 \]
03
Solve the Quadratic Equation
To solve the quadratic equation \(x^2 - 15x - 9450 = 0\), we can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \(a = 1\), \(b = -15\), and \(c = -9450\).
04
Calculate the Discriminant
Compute the discriminant \(b^2 - 4ac\): \[ b^2 - 4ac = (-15)^2 - 4(1)(-9450) = 225 + 37800 = 38025 \] The discriminant is positive, which means there are two real solutions.
05
Apply the Quadratic Formula
Using the quadratic formula, calculate \(x\):\[ x = \frac{-(-15) \pm \sqrt{38025}}{2(1)} = \frac{15 \pm 195}{2} \] Calculate the two solutions: \[ x_1 = \frac{15 + 195}{2} = 105 \] \[ x_2 = \frac{15 - 195}{2} = -90 \]
06
Select the Reasonable Solution
Since \(x\) represents the number of units manufactured, it must be a non-negative integer. Therefore, the acceptable solution is \(x = 105\) because \(x = -90\) is not physically meaningful in this context.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cost Function
In mathematics, a cost function represents the total cost incurred for manufacturing a certain number of units of a product. It is usually expressed as a function of the quantity of goods produced, denoted by a variable such as \(x\). In this exercise, the cost function is given by \(C(x) = x^2 - 15x + 50\). This is a quadratic equation, where:
- \(x\) is the number of units produced
- \(x^2\) represents the increasing costs as production ramps up
- \(-15x\) accounts for linear changes in cost, perhaps due to efficiency improvements
- \(50\) is a fixed cost, unaffected by the number of units produced
Quadratic Formula
The quadratic formula is a fundamental tool used to solve quadratic equations, which are polynomial equations of the form \(ax^2 + bx + c = 0\). The formula is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula provides solutions for \(x\) by calculating the roots of the equation. In the context of the exercise, the quadratic equation \(x^2 - 15x - 9450 = 0\) is solved using this formula.
Here:
Here:
- \(a = 1\)
- \(b = -15\)
- \(c = -9450\)
Discriminant
The discriminant is part of the quadratic formula, located under the square root: \(b^2 - 4ac\). It is used to determine the nature of the roots of a quadratic equation. The value of the discriminant tells us:
- If it's positive, the quadratic equation has two distinct real solutions.
- If it's zero, there is exactly one real solution (a repeated root).
- If it's negative, there are no real solutions, only complex solutions.
Real Solutions
Real solutions to a quadratic equation are the values that satisfy the equation when substituted back into it. These solutions can be found using the quadratic formula, provided the discriminant is non-negative.
In this exercise, after calculating the discriminant and confirming it is positive, we proceed with the quadratic formula.Using \(b^2 - 4ac = 38025\), the roots were calculated:
In this exercise, after calculating the discriminant and confirming it is positive, we proceed with the quadratic formula.Using \(b^2 - 4ac = 38025\), the roots were calculated:
- \(x_1 = 105\)
- \(x_2 = -90\)