Chapter 5: Problem 10
Solve each equation. $$ n^{2}+n=72 $$
Short Answer
Expert verified
The solutions are \( n = -9 \) and \( n = 8 \).
Step by step solution
01
Set Equation to Zero
To solve the equation \( n^2 + n = 72 \), we first need to set it to zero. Subtract 72 from both sides to obtain:\[ n^2 + n - 72 = 0 \]
02
Factor the Quadratic Equation
Now, we will factor the equation \( n^2 + n - 72 = 0 \). We need to find two numbers whose product is \(-72\) and whose sum is \(1\). These numbers are 9 and -8. Thus, the equation can be factored as:\[ (n + 9)(n - 8) = 0 \]
03
Solve for 'n' Using Zero Product Property
Set each factor equal to zero and solve for \( n \):1. \( n + 9 = 0 \) gives \( n = -9 \)2. \( n - 8 = 0 \) gives \( n = 8 \)The solutions to the equation are \( n = -9 \) and \( n = 8 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Quadratics
Factoring quadratics is a method commonly used for solving quadratic equations of the form \( ax^2 + bx + c = 0 \). The goal is to express the quadratic equation as a product of linear factors. These linear factors will be binomials, each set to equal zero to solve for the unknown variable. To factor a quadratic equation, look for two numbers that multiply to give the product of \( a \times c \) (the first number in your expression and the last number after equating to zero). At the same time, these two numbers should add up to give \( b \), the coefficient of the middle term.
In our example, we transformed the equation \( n^2 + n = 72 \) to \( n^2 + n - 72 = 0 \). The product we need is \(-72\) (as \( a = 1\) and \( c = -72\)) and the sum is \(1\), which are achieved with the numbers \(9\) and \(-8\). Therefore, the quadratic factors to \((n + 9)(n - 8)\). Factoring quadratics is crucial as it makes equations easier to solve without using more complex methods like the quadratic formula.
In our example, we transformed the equation \( n^2 + n = 72 \) to \( n^2 + n - 72 = 0 \). The product we need is \(-72\) (as \( a = 1\) and \( c = -72\)) and the sum is \(1\), which are achieved with the numbers \(9\) and \(-8\). Therefore, the quadratic factors to \((n + 9)(n - 8)\). Factoring quadratics is crucial as it makes equations easier to solve without using more complex methods like the quadratic formula.
Zero Product Property
The zero product property is a fundamental algebraic principle employed after factoring a quadratic. According to this property, if the product of two or more factors is zero, at least one of the factors must be zero.
This property is expressed mathematically as:
In the example \((n + 9)(n - 8) = 0\), the zero product property allows us to write two separate equations:
This property is expressed mathematically as:
- If \( a \cdot b = 0 \), then either \( a = 0 \) or \( b = 0 \), or both.
In the example \((n + 9)(n - 8) = 0\), the zero product property allows us to write two separate equations:
- \( n + 9 = 0 \)
- \( n - 8 = 0 \)
Solving Equations
Solving equations fundamentally involves finding the values of the variable that make the equation true. In the context of quadratic equations, the solutions are often called "roots". Once a quadratic is factored and you’ve applied the zero product property, you’re faced with simple linear equations to solve.
In our example, factored as \((n + 9)(n - 8) = 0\), solving the resulting linear equations is straightforward:
In our example, factored as \((n + 9)(n - 8) = 0\), solving the resulting linear equations is straightforward:
- For \( n + 9 = 0 \), subtract 9 from both sides to find \( n = -9 \).
- For \( n - 8 = 0 \), add 8 to both sides to get \( n = 8 \).