/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Solve each system of equations b... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each system of equations by the elimination method. See Examples 7 through 10. $$ \left\\{\begin{array}{r} {5 x+2 y=1} \\ {x-3 y=7} \end{array}\right. $$

Short Answer

Expert verified
The solution is \(x = 1\) and \(y = -2\).

Step by step solution

01

Set Up Equations for Elimination

We have two equations:1. \(5x + 2y = 1\)2. \(x - 3y = 7\).We'll use the elimination method to eliminate one variable. We can target eliminating \(x\) by aligning coefficients. This requires multiplying the second equation by 5.
02

Align the Coefficients

After multiplying the second equation by 5, the system becomes:1. \(5x + 2y = 1\)2. \(5x - 15y = 35\).Now both equations have the same coefficient for \(x\).
03

Subtract Equations to Eliminate a Variable

Subtract the second equation from the first to eliminate \(x\):\((5x + 2y) - (5x - 15y) = 1 - 35\)This simplifies to: \(17y = -34\).
04

Solve for the Remaining Variable

Solve the equation \(17y = -34\) by dividing both sides by 17:\[y = \frac{-34}{17} = -2.\]
05

Substitute Back to Find Second Variable

Substitute \(y = -2\) back into one of the original equations to solve for \(x\). Using \(x - 3y = 7\):\[x - 3(-2) = 7\]\[x + 6 = 7\]Solving for \(x\) gives:\[x = 1.\]
06

Verify the Solution

Substitute \(x = 1\) and \(y = -2\) back into the other original equation (\(5x + 2y = 1\)) to verify:\[5(1) + 2(-2) = 5 - 4 = 1.\]Both sides match, confirming the solution is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equations
A linear equation is a fundamental algebraic concept. It is an equation between two variables that can be graphically represented as a straight line. There is a standard form for linear equations in two variables: \( ax + by = c \), where \(a\), \(b\), and \(c\) are constants and \(x\) and \(y\) are variables. This expression describes a line in a two-dimensional plane.

Linear equations are essential because they allow us to model and solve real-world problems, making them a crucial tool in various fields such as economics, engineering, and physics. They are easy to work with due to their straightforward nature, expanding further into complex areas such as linear algebra.

When working with linear equations, understanding the slope-intercept form \( y = mx + c \) is also imperative. Here, \(m\) is the slope of the line, which tells us how steep the line is, and \(c\) is the y-intercept, the point where the line crosses the y-axis. Mastering these forms allows us to quickly graph a linear equation or understand its properties without much computation.
Systems of Equations
When we talk about systems of equations, this refers to a set of two or more equations that have common variables, as presented in the original exercise. Solving such systems means finding the values of the variables that satisfy all the equations in the set simultaneously.

There are several methods to solve systems of equations, including:
  • Graphical Method: This involves graphing each equation in the system and identifying the point(s) where the graphs intersect, which represent the solution(s).
  • Substitution Method: This involves solving one equation for one variable and then substituting that expression into the other equation. While efficient for simple systems, it can become cumbersome for more complex ones.
  • Elimination Method: This is a strategic approach where you eliminate one of the variables by adding or subtracting equations, as done in the provided solution. This method is powerful when equations align well for manipulation.
Systems of equations are ubiquitous in mathematical modeling. They allow us to solve problems where multiple conditions must be satisfied simultaneously, such as balancing chemical reactions or optimizing business decisions.
Substitution Method
The substitution method is another classic approach for solving systems of equations, closely related to the exercise. It involves isolating one of the variables in one equation and replacing it in the other.

Let's break it down:
  • First, select one of the equations in the system and solve for one variable in terms of the other. This works best when one of the coefficients is 1 or -1, making simplification easy.
  • Next, substitute this expression into the other equation. This step results in a new equation with just one variable, making it easier to solve.
  • Solve the simplified equation to find the value of the isolated variable.
  • Finally, substitute back the obtained value into the equation used initially to express the first variable, to calculate the second variable.
One key advantage of the substitution method is its straightforward nature when handling equations where one variable can be easily isolated. However, it can be cumbersome with more complex coefficients or large systems. Nevertheless, mastering this method, along with others like the elimination method, builds a strong foundation for solving any system of equations effectively.

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Most popular questions from this chapter

Add the equations. See Section 4.1. $$ \begin{array}{l} {10 x+5 y+6 z=14} \\ {-9 x+5 y-6 z=-12} \end{array} $$

Solve each system. To do so, you may want to let \(a=\frac{1}{x}\) (if \(x\) is in the denominator) and let \(b=\frac{1}{y}\) (if \(y\) is in the denominator.) $$ \left\\{\begin{array}{l} {\frac{2}{x}+\frac{3}{y}=5} \\ {\frac{5}{x}-\frac{3}{y}=2} \end{array}\right. $$

Solve each system of equations. $$ \left\\{\begin{array}{r} {0.7 x-0.2 y=-1.6} \\ {0.2 x-y=-1.4} \end{array}\right. $$

The fraction \(\frac{1}{24}\) can be written as the following sum: $$ \frac{1}{24}=\frac{x}{8}+\frac{y}{4}+\frac{z}{3} $$ where the numbers \(x, y,\) and \(z\) are solutions of $$ \left\\{\begin{aligned} x+y+z &=1 \\ 2 x-y+z &=0 \\ -x+2 y+2 z &=-1 \end{aligned}\right. $$ Solve the system and see that the sum of the fractions is \(\frac{1}{24}\)

The amount of U.S. federal government income \(y\) (in billions of dollars) for fiscal year \(x,\) from 2006 through \(2009(x=0\) represents \(2006),\) can be modeled by the linear equation \(y=-95 x+2406 .\) The amount of U.S. federal government expenditures \(y\) (in billions of dollars) for the same period can be modeled by the linear equation \(y=285 x+2655\) (Source: Based on data from Financial Management Service, U.S. Department of the Treasury, \(2006-2009\) ) a. What does the slope of each equation tell you about the patterns of U.S. federal government income and expenditures? b. Solve this system of equations. (Round your final results to the nearest whole numbers.) c. Did expenses ever equal income during the period from 2006 through \(2009 ?\)

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