Chapter 3: Problem 68
Sketch the graph of each piecewise-defined function. Write the domain and range of each function. $$ f(x)=\left\\{\begin{aligned} x^{2} & \text { if } \quad x<0 \\ \sqrt{x} & \text { if } \quad x \geq 0 \end{aligned}\right. $$
Short Answer
Expert verified
The function is defined for all real numbers with a range of \( y \geq 0 \).
Step by step solution
01
Analyze the Function Parts
The given piecewise function is comprised of two parts. The first is \( f(x) = x^2 \) for \( x < 0 \), which is a parabola opening upwards. The second part is \( f(x) = \sqrt{x} \) for \( x \geq 0 \), representing the right half of a sideways parabola.
02
Determine the Domain
The domain is determined by looking at the values for which the function is defined. For \( x^2 \), the domain is \( x < 0 \), and for \( \sqrt{x} \), the domain is \( x \geq 0 \). Therefore, the overall domain of the function is all real numbers.
03
Find the Range of Each Part
For the part \( f(x) = x^2 \) where \( x < 0 \), the range is \( y > 0 \) because the parabola is above the x-axis for negative x-values. For the part \( f(x) = \sqrt{x} \) where \( x \geq 0 \), the range is \( y \geq 0 \) because the square root is defined for non-negative numbers and starts at \( y = 0 \). Together, these parts cover \( y \geq 0 \) for the entire function.
04
Sketch the Graph
Start with the parabola \( f(x) = x^2 \). Since \( x < 0 \), only the left half of this parabola is drawn, opening upwards starting from just left of the y-axis. Then sketch \( f(x) = \sqrt{x} \) for \( x \geq 0 \), starting from the origin (0,0) and increasing slowly to the right.
05
Verify Continuity at the Junction
The junction is at \( x = 0 \). At this point, the value from the function \( \sqrt{x} \) equals 0, while \( x^2 \) for values near 0 would be small positive numbers. The function is continuous at \( x = 0 \) as both parts meet here without gap or jump.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graph Sketching of Piecewise Functions
When sketching the graph of a piecewise function, it is important to treat each piece individually while considering how they come together. In the function given, there are two distinct parts:
- For the interval where \( x < 0 \), the function is described by \( f(x) = x^2 \). This represents a part of the standard parabola opening upwards. However, since \( x < 0 \) limits us to using only the left side of this parabola, we sketch half of it up to but not including the y-axis.
- For \( x \geq 0 \), the function is \( f(x) = \sqrt{x} \). This is the graph of a square root function, starting from the origin and gradually increasing as \( x \) becomes larger.
Domain and Range of Piecewise Functions
Understanding the domain and range of piecewise functions requires analyzing each piece separately. The domain encompasses all x-values that the function can legitimately accept:
- For \( f(x) = x^2 \), \( x < 0 \), meaning this part of the function exists only to the left of the y-axis. Its domain is \( (-\infty, 0) \).
- For \( f(x) = \sqrt{x} \), \( x \geq 0 \), indicating that it applies to x-values from zero onwards. Hence, this segment's domain is \( [0, \infty) \).
- By combining these, the overall domain of the function is \( (-\infty, 0) \cup [0, \infty) \), equating to all real numbers.
- The range from \( f(x) = x^2 \) where \( x < 0 \) is strictly positive values, \( (0, \infty) \), because \( x^2 \) is always positive for any non-zero x.
- The range from \( f(x) = \sqrt{x} \) where \( x \geq 0 \) is \( [0, \infty) \). This square root part allows y to be zero or any positive number, starting from zero and increasing.
- Thus, the total range for the complete function is \( [0, \infty) \).
Function Continuity at Junctions
A critical aspect of piecewise functions is checking for continuity at the points where the individual pieces meet. In our case, this occurs at \( x = 0 \). To verify continuity, the function's value should converge consistently from both sides:
- As \( x \) approaches 0 from the left, employing \( f(x) = x^2 \), the y-values become infinitesimally close to 0. Thus, there is a tendency towards the origin (0,0).
- From the right, with \( f(x) = \sqrt{x} \) applied, the value at exactly \( x = 0 \) is 0. Therefore, the function does not exhibit any break or jump at that point.