Chapter 11: Problem 37
Find a general term \(a_{n}\) for each sequence, whose first four terms are given. See Example 3. $$ \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \frac{1}{81} $$
Short Answer
Expert verified
The general term is \(a_n = \frac{1}{3^n}\).
Step by step solution
01
Identify the pattern
Observe the given sequence which is \( \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \frac{1}{81} \). Notice that each term seems to be a power of 3 in the denominator.
02
Express terms as powers
Express each term of the sequence as powers of 3: \( \frac{1}{3} = \frac{1}{3^1} \), \( \frac{1}{9} = \frac{1}{3^2} \), \( \frac{1}{27} = \frac{1}{3^3} \), \( \frac{1}{81} = \frac{1}{3^4} \).
03
Formulate the general term
Notice that the denominators follow the pattern \(3^1, 3^2, 3^3, 3^4\). Thus, the general term can be represented as \(a_n = \frac{1}{3^n}\).
04
Verify the general term
Substitute different integer values for \(n\) to check if they give the correct terms. For example, when \(n=1\), \(a_1 = \frac{1}{3^1} = \frac{1}{3}\); when \(n=2\), \(a_2 = \frac{1}{3^2} = \frac{1}{9}\); and so forth.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
General Term of a Sequence
In sequences, finding the general term is like cracking a secret code. The general term allows you to see the pattern and predict any term in the sequence. For the sequence given, the terms are \( \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \frac{1}{81} \). Our mission is to identify a formula that can generate these terms in such an order.
This formula or general term is usually described using an index, often "n". For this sequence, after a bit of exploration, it becomes clear that each denominator is a power of 3. Therefore, the general term for this sequence is \( a_n = \frac{1}{3^n} \). By using this formula, you can calculate any term in the sequence by simply substituting \( n \) with the term's position number.
This formula or general term is usually described using an index, often "n". For this sequence, after a bit of exploration, it becomes clear that each denominator is a power of 3. Therefore, the general term for this sequence is \( a_n = \frac{1}{3^n} \). By using this formula, you can calculate any term in the sequence by simply substituting \( n \) with the term's position number.
Pattern Recognition
Pattern recognition is key to understanding sequences. By observing the sequence: \( \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \frac{1}{81} \), you need to look for underlying regularities. In this particular sequence, each term seems to have a clear and recurring method of organization in its denominator.
One effective way to solve a problem like this is by looking for a consistent pattern or progression. For these terms, the sequence in the denominator hints at a progression of powers of 3. Once you recognize it, calculating further terms becomes much easier. Thus, pattern recognition isn't just helpful; it's an essential step in solving sequence-related problems.
One effective way to solve a problem like this is by looking for a consistent pattern or progression. For these terms, the sequence in the denominator hints at a progression of powers of 3. Once you recognize it, calculating further terms becomes much easier. Thus, pattern recognition isn't just helpful; it's an essential step in solving sequence-related problems.
Denominator as Powers
In mathematical sequences where numbers exhibit regularity in multiplication or division, identifying terms like powers is crucial. Here, the sequence: \( \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \frac{1}{81} \) shows a repeated pattern that can be expressed with exponents.
For example, look at how the denominators evolve:
For example, look at how the denominators evolve:
- \( 3 \) can be written as \( 3^1 \)
- \( 9 \) (which is \( 3 \times 3 \)) as \( 3^2 \)
- \( 27 \) (\( 3 \times 3 \times 3 \)) as \( 3^3 \)
- \( 81 \) (\( 3 \times 3 \times 3 \times 3 \)) as \( 3^4 \)
Verifying a Sequence
After formulating a general term, it's vital to verify it to ensure accuracy. You can do this by plugging values into your general term equation. For this sequence, let's check:
This shows that the general term \( a_n = \frac{1}{3^n} \) correctly predicts each term of the sequence. This validation step confirms that your pattern recognition and formulation of the general term were both correct.
- For \( n = 1 \), the term is \( a_1 = \frac{1}{3^1} = \frac{1}{3} \)
- For \( n = 2 \), it becomes \( a_2 = \frac{1}{3^2} = \frac{1}{9} \)
- For \( n = 3 \), it's \( a_3 = \frac{1}{3^3} = \frac{1}{27} \)
- For \( n = 4 \), \( a_4 = \frac{1}{3^4} = \frac{1}{81} \)
This shows that the general term \( a_n = \frac{1}{3^n} \) correctly predicts each term of the sequence. This validation step confirms that your pattern recognition and formulation of the general term were both correct.