Chapter 10: Problem 20
The graph of each equation is a parabola. Find the vertex of the parabola and then graph it. $$y=x^{2}+4 x-5$$
Short Answer
Expert verified
The vertex of the parabola is (-2, -9).
Step by step solution
01
Identify the Standard Form of a Parabola
The given equation is \( y = x^2 + 4x - 5 \). This is a quadratic equation in the standard form \( y = ax^2 + bx + c \), where \( a = 1 \), \( b = 4 \), and \( c = -5 \).
02
Find the x-coordinate of the Vertex
The x-coordinate of the vertex of a parabola in the form \( y = ax^2 + bx + c \) is given by the formula \( x = -\frac{b}{2a} \). Substituting the values, we calculate \( x = -\frac{4}{2 \cdot 1} = -2 \).
03
Find the y-coordinate of the Vertex
Substitute the x-coordinate \( x = -2 \) into the original equation to find the y-coordinate. \( y = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -9 \). Thus, the vertex is (-2, -9).
04
Plot the Vertex and Graph the Parabola
Plot the vertex (-2, -9) on a coordinate grid. Since the coefficient of \( x^2 \) is positive, the parabola opens upward. You can plot additional points by substituting other x-values into the equation, ensuring symmetry about the vertex.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Form of Quadratic Equation
Understanding the standard form of a quadratic equation is the first step in identifying and analyzing parabolas. The standard form is expressed as \(y = ax^2 + bx + c\). Here,
- \(a\) is the coefficient of \(x^2\), which influences the "width" and "direction" of the parabola (whether it opens upwards or downwards).
- \(b\) is the coefficient of \(x\), impacting the "location" of the parabola along the x-axis.
- \(c\) is the constant term, determining the "y-intercept," the point at which the parabola crosses the y-axis.
Quadratic Formula
The vertex of a parabola is a crucial feature that indicates its highest or lowest point. For any quadratic equation in standard form \(y = ax^2 + bx + c\), the x-coordinate of the vertex can be efficiently calculated using the formula \(x = -\frac{b}{2a}\). To find the vertex for our given equation:1. Identify \(a\), \(b\), and \(c\).2. Plug these values into the formula to determine the x-coordinate.In this case, \(a = 1\) and \(b = 4\), leading to \(x = -\frac{4}{2 \cdot 1} = -2\).To find the y-coordinate, substitute \(x = -2\) back into the quadratic equation:\[y = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -9\]Thus, the vertex of the parabola for this equation is \((-2, -9)\). Understanding this step significantly aids in visualizing the shape and position of the parabola.
Graphing Parabolas
Graphing a parabola involves plotting its key components accurately on a coordinate plane. Start by marking the vertex, which in this case is \((-2, -9)\). The direction the parabola opens—that is, whether it curves up or down—depends on the coefficient \(a\). When \(a > 0\), as with \(y = x^2 + 4x - 5\), the parabola opens upward. To plot the parabola:
- Start by plotting the vertex point, establishing the parabola's central axis.
- Choose additional points on each side of the vertex to show the parabola's shape. Substituting x-values into the equation gives corresponding y-values.
- Draw a smooth curve through these points, ensuring the curve is symmetric about the vertex's vertical line.