Chapter 8: Problem 94
Solve each equation. Approximate the solutions to the nearest hundredth when appropriate. $$ 3 m^{2}-2 m+3=0 $$
Short Answer
Expert verified
The solutions are \( m = \frac{1}{3} + \frac{2\sqrt{2}}{3}i \) and \( m = \frac{1}{3} - \frac{2\sqrt{2}}{3}i \).
Step by step solution
01
Identify the Equation Type
The given equation is a quadratic equation, which is in the form \( ax^2 + bx + c = 0 \). Here, \( a = 3 \), \( b = -2 \), and \( c = 3 \).
02
Calculate the Discriminant
The discriminant of a quadratic equation \( ax^2 + bx + c = 0 \) is given by \( b^2 - 4ac \). It helps determine the nature of the roots. For this equation, the discriminant is \((-2)^2 - 4 \cdot 3 \cdot 3 = 4 - 36 = -32\).
03
Analyze the Discriminant
Since the discriminant is negative (\(-32\)), this indicates that the quadratic equation does not have real roots. Instead, it has two complex roots.
04
Use the Quadratic Formula for Complex Roots
The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). For complex solutions, where \( b^2 - 4ac < 0 \), the solutions involve complex numbers. Thus, \( m = \frac{2 \pm \sqrt{-32}}{6} \).
05
Simplify the Complex Roots
The term \( \sqrt{-32} \) can be rewritten using \( i \) (the imaginary unit) as \( \sqrt{32}i = 4\sqrt{2}i \). Therefore, \( m = \frac{2 \pm 4\sqrt{2}i}{6} \).
06
Express the Solutions
Divide each term by 6 to simplify: \( m = \frac{2}{6} \pm \frac{4\sqrt{2}}{6}i \). This further simplifies to: \[ m = \frac{1}{3} \pm \frac{2\sqrt{2}}{3}i \]. Thus, the solutions are \( m = \frac{1}{3} + \frac{2\sqrt{2}}{3}i \) and \( m = \frac{1}{3} - \frac{2\sqrt{2}}{3}i \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
The discriminant is a key concept in understanding quadratic equations. It helps us determine the nature of the roots without actually solving the entire equation. For any quadratic equation of the form \( ax^2 + bx + c = 0 \), the discriminant is given by the expression \( b^2 - 4ac \).
This value is crucial because it tells us whether the solutions to the quadratic equation are real or complex:
This value is crucial because it tells us whether the solutions to the quadratic equation are real or complex:
- If the discriminant is positive, there are two distinct real roots.
- If it is zero, there is exactly one real root, also known as a repeated or double root.
- If the discriminant is negative, as in the above exercise where \( b^2 - 4ac = -32 \), there are no real roots. Instead, the equation has two complex roots, which involve imaginary numbers.
Complex Roots
When the discriminant is negative, as it is in the exercise with a value of \(-32\), the quadratic equation does not intersect the x-axis, which means it has no real roots. Instead, it has complex roots. Complex roots arise from the square root of a negative number which involves the imaginary unit \( i \), where \( i^2 = -1 \).
Using the quadratic formula, the roots can be expressed as \( m = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). In the case of a negative discriminant, you'll have \( \pm \sqrt{-32} \), which converts to \( 4\sqrt{2}i \) (since \( \sqrt{-32} = 4\sqrt{2}i \)). Therefore, the solutions include both real and imaginary parts:
Using the quadratic formula, the roots can be expressed as \( m = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). In the case of a negative discriminant, you'll have \( \pm \sqrt{-32} \), which converts to \( 4\sqrt{2}i \) (since \( \sqrt{-32} = 4\sqrt{2}i \)). Therefore, the solutions include both real and imaginary parts:
- Real part: \( \frac{1}{3} \)
- Imaginary part: \( \frac{2\sqrt{2}}{3}i \)
Quadratic Formula
The quadratic formula is a powerful tool for solving any quadratic equation of the form \( ax^2 + bx + c = 0 \). It provides a direct way to find the roots of the equation, which are the values of \( x \) that satisfy the equation.
The formula is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Here's how it works:
The formula is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Here's how it works:
- The term \(-b\) indicates the factor opposite to the linear coefficient.
- The \( \pm \) symbol highlights the possibility of two solutions: one with addition and one with subtraction.
- The expression \( \sqrt{b^2 - 4ac} \) is the discriminant discussed earlier, central to determining the root nature.
- Everything is divided by \( 2a \), which is twice the coefficient of \( x^2 \).