Chapter 8: Problem 78
Solve each equation. Approximate the solutions to the nearest hundredth when appropriate. $$ 5 x^{2}+40=0 $$
Short Answer
Expert verified
The solutions are \(x = \pm 2\sqrt{2}i\).
Step by step solution
01
Isolate the Squared Term
Begin by moving the constant term to the right side of the equation by subtracting 40 from both sides, resulting in: \[ 5x^2 = -40 \]
02
Solve for the Squared Term
Divide both sides by 5 to solve for \(x^2\):\[ x^2 = -8 \]
03
Consider the Nature of the Solution
Recognize that \(x^2 = -8\) indicates that the solution involves imaginary numbers, as there is no real number that squares to a negative value.
04
Find the Imaginary Solution
Take the square root of both sides, remembering to include the imaginary unit \(i\), which denotes \(\sqrt{-1}\):\[ x = \pm \sqrt{-8} = \pm \sqrt{-1 \times 8} = \pm \sqrt{8}i \]
05
Simplify the Square Root
Simplify \(\sqrt{8}\):\[ \sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2} \]Thus, the solutions are:\[ x = \pm 2\sqrt{2}i \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are mathematical expressions that follow the standard form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants with \( a eq 0 \). These equations are fundamental in algebra and appear in many real-world contexts, such as physics and engineering. The solutions to a quadratic equation can be found using various methods, including factoring, completing the square, and the quadratic formula.
In the exercise provided, we started with the equation \( 5x^2 + 40 = 0 \), which is already in its simplest form for a quadratic without a linear term. The task is to find the values of \( x \) that satisfy this equation. A key aspect of working with quadratics is identifying when the solutions might involve complex numbers, which commonly occurs if the equation involves a negative square root.
This problem highlights an essential skill in algebra: understanding when a solution will involve imaginary numbers, particularly when the squared term results in a negative value.
In the exercise provided, we started with the equation \( 5x^2 + 40 = 0 \), which is already in its simplest form for a quadratic without a linear term. The task is to find the values of \( x \) that satisfy this equation. A key aspect of working with quadratics is identifying when the solutions might involve complex numbers, which commonly occurs if the equation involves a negative square root.
This problem highlights an essential skill in algebra: understanding when a solution will involve imaginary numbers, particularly when the squared term results in a negative value.
Complex Solutions
Complex solutions emerge when dealing with non-real numbers, particularly roots of negative numbers. In the context of quadratic equations, if the discriminant \( b^2 - 4ac \) is less than zero, the solutions are complex. This means they include the imaginary unit \( i \), where \( i = \sqrt{-1} \).
When faced with \( x^2 = -8 \), it's apparent that no real number squared will give a negative result. Here, complex solutions come into play. Using the imaginary unit \( i \), any negative under a square root is transformed into an imaginary number. For our exercise, that meant computing \( x = \pm \sqrt{-8} = \pm \sqrt{8}i \).
Understanding complex solutions allows for solving quadratic equations that don't intersect the x-axis on a graph, representing situations with no real number solutions but rather solutions that exist in the complex plane.
When faced with \( x^2 = -8 \), it's apparent that no real number squared will give a negative result. Here, complex solutions come into play. Using the imaginary unit \( i \), any negative under a square root is transformed into an imaginary number. For our exercise, that meant computing \( x = \pm \sqrt{-8} = \pm \sqrt{8}i \).
Understanding complex solutions allows for solving quadratic equations that don't intersect the x-axis on a graph, representing situations with no real number solutions but rather solutions that exist in the complex plane.
Square Roots
The square root operation involves finding a number that, when multiplied by itself, returns the original number. When working with square roots of negative numbers, the concept of imaginary numbers plays a crucial role. Regular square root operations, such as \( \sqrt{9} = 3 \), yield real numbers, but \( \sqrt{-9} \) moves into the realm of complex numbers.
In the step-by-step solution provided in the exercise, the equation \( x^2 = -8 \) required taking the square root of both sides. The appearance of a negative number under the square root suggests using the imaginary unit \( i \). Simplifying \( \sqrt{-8} \) involves breaking it into \( \sqrt{8}i \).
To simplify \( \sqrt{8} \), break it down further using its factorization: \( \sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2} \). Thus, the fully simplified complex solutions are \( x = \pm 2\sqrt{2}i \). Understanding square roots, especially in complex scenarios, aids in solving a broader range of algebraic challenges.
In the step-by-step solution provided in the exercise, the equation \( x^2 = -8 \) required taking the square root of both sides. The appearance of a negative number under the square root suggests using the imaginary unit \( i \). Simplifying \( \sqrt{-8} \) involves breaking it into \( \sqrt{8}i \).
To simplify \( \sqrt{8} \), break it down further using its factorization: \( \sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2} \). Thus, the fully simplified complex solutions are \( x = \pm 2\sqrt{2}i \). Understanding square roots, especially in complex scenarios, aids in solving a broader range of algebraic challenges.