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Solve each equation. Approximate the solutions to the nearest hundredth when appropriate. $$ \frac{a^{2}}{10}-\frac{3 a}{5}+\frac{7}{5}=0 $$

Short Answer

Expert verified
The solutions are \( a = 3 + i\sqrt{5} \) and \( a = 3 - i\sqrt{5} \).

Step by step solution

01

Identify the Equation Components

The equation given is \( \frac{a^{2}}{10} - \frac{3a}{5} + \frac{7}{5} = 0 \). This is a quadratic equation of the form \( ax^2 + bx + c = 0 \), where the coefficients are fractions.
02

Clear Fractions by Multiplying by 10

To simplify the equation and remove fractions, multiply every term by 10. This gives \( a^2 - 6a + 14 = 0 \).
03

Use the Quadratic Formula

Since the equation is \( a^2 - 6a + 14 = 0 \), apply the quadratic formula: \[ a = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]where \( a = 1 \), \( b = -6 \), and \( c = 14 \).
04

Calculate the Discriminant

Calculate the discriminant \( b^2 - 4ac = (-6)^2 - 4 \times 1 \times 14 = 36 - 56 = -20 \).
05

Determine the Nature of the Roots

Since the discriminant is negative (\(-20\)), the solutions are complex numbers. Use \( i \), the imaginary unit, where \( i = \sqrt{-1} \).
06

Compute the Solutions

Use the quadratic formula to find the roots:\[ a = \frac{-(-6) \pm \sqrt{-20}}{2 \times 1} \]This simplifies to:\[ a = \frac{6 \pm i\sqrt{20}}{2} \]Further simplify \( \sqrt{20} \) as \( 2\sqrt{5} \):\[ a = 3 \pm i\sqrt{5} \]
07

Conclude the Solution Process

Thus, the solutions to the equation are complex numbers \( a = 3 + i\sqrt{5} \) and \( a = 3 - i\sqrt{5} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
Complex numbers are numbers that have a real part and an imaginary part. They are written in the form \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part that includes the imaginary unit \( i \).
These numbers extend the concept of one-dimensional number lines into two-dimensional planes.
Complex numbers are incredibly important in advanced mathematics and engineering, as they allow for a better understanding of systems that cannot be explained by real numbers alone.
  • The real part \( a \) determines the horizontal position on the complex plane.
  • The imaginary part \( bi \) determines the vertical position.
When we solve a quadratic equation and find that the discriminant \( b^2 - 4ac \) is negative, that tells us that our equation has complex roots, as you saw in the step-by-step exercise.
By understanding these numbers, you can handle solutions that might seem unsettling at first but are quite common in advanced calculations.
Quadratic Formula
The quadratic formula is a universal solution for quadratic equations of the form \( ax^2 + bx + c = 0 \).
It is given by the formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula provides the solution(s) for any quadratic equation, without the need for factoring or completing the square, which can sometimes be cumbersome.
In the step-by-step solution, you used this formula after simplifying to find the potential roots for the equation \( a^2 - 6a + 14 = 0 \). Here are some handy tips:
  • First, identify the coefficients \(a, b, c\).
  • Calculate the discriminant \(b^2 - 4ac\).
  • Use the quadratic formula, inserting your values and solving for \(x\).
  • If the discriminant is negative, expect complex roots.
Using the quadratic formula helps in guaranteeing a solution, even for equations that cannot be factored neatly.
Imaginary Unit
The imaginary unit, denoted as \( i \), is the fundamental building block of complex numbers. It is defined as the square root of \(-1\):
\[ i = \sqrt{-1} \]This may seem strange because nothing squared equals a negative number in the real number system, but with \( i \), it becomes possible.
An imaginary number is a real number multiplied by \( i \); for instance, \( 3i \) means that 3 is the imaginary part.
When you come across a negative discriminant in a quadratic equation, you use \( i \) to express the roots.
  • \( i^2 = -1 \)
  • Combining real and imaginary numbers gives us complex numbers.
  • Imaginary numbers lie on the vertical axis of the complex plane.
In our example, the negative discriminant necessitated the use of \( i \), leading to the final solutions expressed as \( 3 \pm i\sqrt{5} \). This signifies the imaginary parts in the roots of the given quadratic equation.

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