Chapter 8: Problem 60
Find the \(x\) -and \(y\) -intercepts of the graph of the quadratic function. See Example \(9 .\) $$ f(x)=-x^{2}-10 x-21 $$
Short Answer
Expert verified
The y-intercept is (0, -21). The x-intercepts are (-7, 0) and (-3, 0).
Step by step solution
01
Understanding the Intercepts
The **x-intercepts** of a function are the points where the graph crosses the x-axis. At these points, the y-value (or f(x)) is zero. Similarly, the **y-intercept** is where the graph crosses the y-axis, with the x-value being zero.
02
Finding the y-intercept
To find the y-intercept, substitute 0 for x in the function and solve for f(x):\[-f(0) = -0^2 - 10(0) - 21 = -21.\]Thus, the y-intercept is at the point (0, -21).
03
Setting up the Quadratic for x-intercepts
The x-intercepts occur where \(f(x) = 0\). Therefore, solve the equation \[-x^2 - 10x - 21 = 0.\]Use this equation to find the x-values where the parabola crosses the x-axis.
04
Using the Quadratic Formula
The expression is a quadratic equation in standard form: \(ax^2 + bx + c = 0\), where \(a = -1\), \(b = -10\), and \(c = -21\). Use the quadratic formula to solve this: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.\] Substituting the values: \[x = \frac{-(-10) \pm \sqrt{(-10)^2 - 4(-1)(-21)}}{2(-1)}.\]
05
Calculating the Discriminant
Calculate the discriminant \(b^2 - 4ac\): \[(-10)^2 - 4(-1)(-21) = 100 - 84 = 16.\] Since the discriminant is positive, there will be two real x-intercepts.
06
Solving for x using the Discriminant
Now substitute the discriminant into the quadratic formula: \[x = \frac{10 \pm \sqrt{16}}{-2}.\] Evaluate \(\sqrt{16} = 4\), so \[x = \frac{10 \pm 4}{-2}.\]
07
Simplifying the Quadratic Formula
Calculate the two possible solutions: \[x = \frac{10 + 4}{-2} = -7\]and \[x = \frac{10 - 4}{-2} = -3.\] Therefore, the x-intercepts are at \((-7, 0)\) and \((-3, 0)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding x-intercepts
The x-intercepts of a quadratic function are the points on the graph where the curve crosses the x-axis. At these points, the value of the function, also known as the y-value or f(x), is zero. To find the x-intercepts, we set the quadratic equation equal to zero and solve for x. These solutions represent where the parabola touches or cuts through the x-axis.
In the problem, the quadratic function is given by \( f(x) = -x^2 - 10x - 21 \). To find the x-intercepts, you need to determine the values of x for which \( f(x) = 0 \). This involves solving the equation \( -x^2 - 10x - 21 = 0 \). By solving this equation, you would find the points where the graph intersects the x-axis, yielding the x-intercepts.
In the problem, the quadratic function is given by \( f(x) = -x^2 - 10x - 21 \). To find the x-intercepts, you need to determine the values of x for which \( f(x) = 0 \). This involves solving the equation \( -x^2 - 10x - 21 = 0 \). By solving this equation, you would find the points where the graph intersects the x-axis, yielding the x-intercepts.
Finding the y-intercept
The y-intercept of a function is the point where the graph crosses the y-axis. At this point, the value of x is zero. To find the y-intercept of a quadratic function, we substitute 0 for x in the function, and then solve for \( f(x) \).
For the quadratic function \( f(x) = -x^2 - 10x - 21 \), substitute 0 for x:
For the quadratic function \( f(x) = -x^2 - 10x - 21 \), substitute 0 for x:
- \( -f(0) = -0^2 - 10 \times 0 - 21 = -21 \)
Introduction to the Quadratic Formula
The quadratic formula is a reliable method for finding the x-intercepts of any quadratic function. A quadratic equation is generally in the form \( ax^2 + bx + c = 0 \). The quadratic formula is:
Using the quadratic function \( f(x) = -x^2 - 10x - 21 \), we identify:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Using the quadratic function \( f(x) = -x^2 - 10x - 21 \), we identify:
- \( a = -1 \)
- \( b = -10 \)
- \( c = -21 \)
Exploring the Discriminant
The discriminant is a component of the quadratic formula that can tell us about the nature of the roots of a quadratic equation. It is the part under the square root: \( b^2 - 4ac \). Depending on its value, the discriminant indicates the number and type of solutions:
- If the discriminant is positive, there are two distinct real solutions (two x-intercepts).
- If the discriminant is zero, there is exactly one real solution (the vertex of the parabola touches the x-axis).
- If the discriminant is negative, there are no real solutions (the parabola does not cross the x-axis).
- \((-10)^2 - 4 \times (-1) \times (-21) = 100 - 84 = 16 \)