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Use the square root property to solve each equation. See Example 1. $$ x^{2}-35=0 $$

Short Answer

Expert verified
The solutions are \(x = \pm \sqrt{35}\).

Step by step solution

01

Understand the Square Root Property

The square root property states that if you have an equation in the form of \(x^2 = a\), then \(x = \pm \sqrt{a}\). This means that you can take the square root of both sides to solve for \(x\).
02

Isolate the Square Term

Given the equation \(x^2 - 35 = 0\), you need to isolate the \(x^2\) term. To do this, add 35 to both sides of the equation to get \(x^2 = 35\).
03

Apply the Square Root Property

Now that the equation is \(x^2 = 35\), apply the square root property. Take the square root of both sides to find \(x = \pm \sqrt{35}\).
04

Simplify if Possible

Check if \(\sqrt{35}\) can be simplified further. Since 35 is not a perfect square and cannot be factored into smaller square numbers, \(\sqrt{35}\) remains as is.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
Quadratic equations are a fundamental concept in algebra that appear in various mathematical contexts. These are polynomial equations of the second degree, generally written in the standard form: \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(a eq 0\). The solutions to these equations are called the roots or zeros of the equation.

Quadratic equations have several methods for finding solutions, including factoring, completing the square, using the quadratic formula, and the square root property. Each method is useful depending on the specific form of the quadratic equation you encounter.

The square root property is employed when the quadratic equation has a simple structure, often only involving the square of a single variable. Learning when and how to effectively use each method is important for efficiently solving quadratics.
Solving Equations
Solving equations involves finding the value(s) of the variable that make the equation true. For quadratic equations, solving typically means finding two values for the variable that satisfy the equation.

To solve the given equation \(x^2 - 35 = 0\), you need to isolate the square term first. This involves rearranging the terms so that the square term is on one side of the equation and constants on the other.
  • Add the constant from the left side to both sides to get \(x^2 = 35\).
  • Isolating the square term simplifies the application of the square root property.

Once isolated, you can proceed with the square root operation on both sides of the equation. This allows you to solve for the variable effectively.
Algebraic Solutions
Algebraic solutions refer to the methods used to solve equations involving algebraic expressions. In context with the equation \(x^2 = 35\), the square root property is used to solve for \(x\).

The square root property simplifies solving equations where the variable is squared, as it suggests that \(x = \pm \sqrt{a}\) when the equation is in the form \(x^2 = a\).
  • Apply the square root to both sides of the equation to get the solutions: \(x = \pm \sqrt{35}\).
  • The \(\pm\) indicates that there are generally two solutions, one positive and one negative, which is characteristic of quadratic equations.

Understanding how and when to apply these procedures is key to solving quadratics swiftly and accurately.

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Most popular questions from this chapter

Use a graphing calculator to solve each equation. If an answer is not exact, round to the nearest hundredth. See Using Your Calculator: Solving Quadratic Equations Graphically. Fireworks. \(\quad\) A fireworks shell is shot straight up with an initial velocity of 120 feet per second. Its height \(s\) in feet after \(t\) seconds is approximated by the equation \(s=120 t-16 t^{2} .\) If the shell is designed to explode when it reaches its maximum height, how long after being fired, and at what height, will the fireworks appear in the sky?

An architect needs to determine the height \(h\) of the window shown in the illustration. The radius \(r,\) the width \(w,\) and the height \(h\) of the circular- shaped window are related by the formula \(r=\frac{4 h^{2}+w^{2}}{8 h} .\) If \(w\) is to be 34 inches and \(r\) is to be 18 inches, find \(h\) to the nearest tenth of an inch. (IMAGE CAN'T COPY)

On an exam, a student was asked to solve the equation \(-4 w^{2}-6 w-1=0 .\) Her first step was to multiply both sides of the equation by \(-1 .\) She then used the quadratic formula to solve \(4 w^{2}+6 w+1=0\) instead. Is this a valid approach? Explain.

Let \(f(x)=0.7 x^{2}-3.5 x .\) For what value(s) of \(x\) is \(f(x)=25 ?\)

Maximizing Revenue. When priced at \(\$ 30\) each, a toy has annual sales of \(4,000\) units. The manufacturer estimates that each S1 increase in price will decrease sales by 100 units. Find the unit price that will maximize total revenue. (Hint: Total revenue \(=\) price \(\cdot\) the number of units sold.)

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