Chapter 5: Problem 77
Solve each equation. $$ \frac{x^{2}(6 x+37)}{35}=x $$
Short Answer
Expert verified
The solutions are \(x = 0\), \(x = \frac{5}{6}\), and \(x = -7\).
Step by step solution
01
Eliminate the Fraction
Start by multiplying both sides of the equation by 35 to eliminate the fraction: \[x^2(6x + 37) = 35x\]
02
Rearrange into a Polynomial Equation
Subtract 35x from both sides to bring the equation to a standard polynomial form:\[x^2(6x + 37) - 35x = 0\]Simplify it to:\[6x^3 + 37x^2 - 35x = 0\]
03
Factor Out the Common Term
Factor an \(x\) from the entire equation:\[x(6x^2 + 37x - 35) = 0\]This step gives us one solution directly: \(x = 0\).
04
Solve the Quadratic Equation
Now, focus on the quadratic part: \[6x^2 + 37x - 35 = 0\]Use the quadratic formula: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Here, \(a = 6\), \(b = 37\), and \(c = -35\).
05
Calculate the Discriminant
Compute the discriminant (\(b^2 - 4ac\)):\[37^2 - 4(6)(-35) = 1369 + 840 = 2209\]The discriminant is a perfect square.
06
Apply the Quadratic Formula
Since the discriminant is a perfect square, apply the formula:\[x = \frac{-37 \pm \sqrt{2209}}{12}\]This simplifies to:\[x = \frac{-37 \pm 47}{12}\]
07
Find the Quadratic Solutions
Evaluate both possibilities for \(x\):1. \(x = \frac{-37 + 47}{12} = \frac{10}{12} = \frac{5}{6}\)2. \(x = \frac{-37 - 47}{12} = \frac{-84}{12} = -7\)
08
Compile All Solutions
The solutions to the equation are:\(x = 0\), \(x = \frac{5}{6}\), and \(x = -7\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations, which are equations of the form \(ax^2 + bx + c = 0\). It provides a simple way to find the roots of the equation by substituting the values of \(a\), \(b\), and \(c\) into the formula:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula is useful because it works for any quadratic equation, regardless of whether the equation can be easily factored or not.
- \(a\): Coefficient of \(x^2\)
- \(b\): Coefficient of \(x\)
- \(c\): Constant term
Discriminant
The discriminant is a key part of the quadratic formula found under the square root: \(b^2 - 4ac\). It tells us about the nature of the roots of the quadratic equation:
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root (a repeated root).
- If the discriminant is negative, the roots are complex or imaginary numbers.
Factoring Polynomials
Factoring polynomials is the process of breaking down a polynomial into simpler components called factors. This method is particularly useful when dealing with polynomial equations, as it can often provide solutions in a faster and more straightforward manner.
For the equation \(6x^3 + 37x^2 - 35x = 0\), the first step in factoring is to extract the greatest common factor (GCF), which in this case is \(x\):\[x(6x^2 + 37x - 35) = 0\]After factoring out \(x\), one solution immediately becomes apparent: \(x = 0\).
Next, focus on factoring the remaining quadratic \(6x^2 + 37x - 35 = 0\). This can sometimes be done by trial and error or by using methods like the quadratic formula.
Factoring is a fundamental skill in algebra as it simplifies solving polynomial equations and can provide insight into the structure of the polynomial.
For the equation \(6x^3 + 37x^2 - 35x = 0\), the first step in factoring is to extract the greatest common factor (GCF), which in this case is \(x\):\[x(6x^2 + 37x - 35) = 0\]After factoring out \(x\), one solution immediately becomes apparent: \(x = 0\).
Next, focus on factoring the remaining quadratic \(6x^2 + 37x - 35 = 0\). This can sometimes be done by trial and error or by using methods like the quadratic formula.
Factoring is a fundamental skill in algebra as it simplifies solving polynomial equations and can provide insight into the structure of the polynomial.