Chapter 2: Problem 68
Complete table. \(f(r)=-2 r^{2}+1\) \(\begin{array}{|r|l|}\hline \text { Input } & \text { Output } \\\\\hline-1.7 & \\\0.9 & \\\5.4 & \\\\\hline\end{array}\)
Short Answer
Expert verified
The outputs are -4.78 for -1.7, -0.62 for 0.9, and -57.32 for 5.4.
Step by step solution
01
Expression of the function
We are given the function \( f(r) = -2r^2 + 1 \). This function takes a value of \( r \) as input and calculates the output \( f(r) \).
02
Calculate the output for \( r = -1.7 \)
Substitute \( r = -1.7 \) into the function: \[f(-1.7) = -2(-1.7)^2 + 1\]Calculate \((-1.7)^2\):\[(-1.7)^2 = 2.89\]Now substitute \(2.89\) back into the expression:\[f(-1.7) = -2(2.89) + 1 = -5.78 + 1 = -4.78\]Thus, the output for \( r = -1.7 \) is \(-4.78\).
03
Calculate the output for \( r = 0.9 \)
Substitute \( r = 0.9 \) into the function:\[f(0.9) = -2(0.9)^2 + 1\]Calculate \((0.9)^2\):\[(0.9)^2 = 0.81\]Now substitute \(0.81\) back into the expression:\[f(0.9) = -2(0.81) + 1 = -1.62 + 1 = -0.62\]Thus, the output for \( r = 0.9 \) is \(-0.62\).
04
Calculate the output for \( r = 5.4 \)
Substitute \( r = 5.4 \) into the function:\[f(5.4) = -2(5.4)^2 + 1\]Calculate \((5.4)^2\):\[(5.4)^2 = 29.16\]Now substitute \(29.16\) back into the expression:\[f(5.4) = -2(29.16) + 1 = -58.32 + 1 = -57.32\]Thus, the output for \( r = 5.4 \) is \(-57.32\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Function
A quadratic function is a type of algebraic expression that includes an unknown variable squared, such as an equation of the form \( ax^2 + bx + c \). This means that there are three components: a quadratic term (\( ax^2 \)), a linear term (\( bx \)), and a constant term (\( c \)). In our exercise, the function we are working with is \( f(r) = -2r^2 + 1 \). Here, the quadratic term is \(-2r^2\) and the constant term is \(+1\). Notice there is no linear term in this function, which makes it a simpler form of quadratic function.
A key feature of quadratic functions is their graph, which takes the shape of a parabola. This can open upwards or downwards depending on the coefficients involved. For our specific function, the coefficient of the squared term \(-2\) is negative, which means the parabola opens downwards.
A key feature of quadratic functions is their graph, which takes the shape of a parabola. This can open upwards or downwards depending on the coefficients involved. For our specific function, the coefficient of the squared term \(-2\) is negative, which means the parabola opens downwards.
Input-Output Table
An input-output table is a convenient way to organize and visualize the results of substituting different values into a function. In our context, the input is the value we assign to the variable \( r \) within the quadratic function , and the output is the result of performing the calculations in the function based on this input.
Creating such a table helps us understand the relationship between inputs and outputs, providing a clear picture of how the function behaves as the input changes. For example, when we input different values like \(-1.7\), \(0.9\), and \(5.4\) into the function \( f(r) = -2r^2 + 1 \), we obtain unique outputs that tell us about the nature of the parabola and the impact each input value has.
Creating such a table helps us understand the relationship between inputs and outputs, providing a clear picture of how the function behaves as the input changes. For example, when we input different values like \(-1.7\), \(0.9\), and \(5.4\) into the function \( f(r) = -2r^2 + 1 \), we obtain unique outputs that tell us about the nature of the parabola and the impact each input value has.
Substitution Method
The substitution method is a fundamental algebraic technique used to find an output by replacing a variable within an expression or function with a specific value. To apply this method to evaluate a function like \( f(r) = -2r^2 + 1 \), we follow these steps:
- Pick a specific value for the input variable (e.g., \( r = -1.7 \)).
- Replace the variable \( r \) in the function with this value, creating a new expression.
- Perform the arithmetic operations: This includes squaring the value, multiplying by the constant outside the squared term, and adding the constant term.
- Calculate the final result to discover the corresponding output.
Algebraic Expression
An algebraic expression is a mathematical phrase that can include numbers, variables, and arithmetic operations. In our exercise, we are analyzing \( f(r) = -2r^2 + 1 \), which is a classic example of an algebraic expression involving both constants and variables.
This expression features a coefficient \(-2\) multiplied by the square of the variable \( r \), showing the impact of squaring \( r \) and then scaling it by \(-2\). Finally, \(+1\) is added to adjust the output.
Algebraic expressions like this one are the building blocks for functions and equations in algebra. They give us the framework to model real-world phenomena and solve problems. Understanding how to manipulate and evaluate these expressions is essential for progressing in mathematics.
This expression features a coefficient \(-2\) multiplied by the square of the variable \( r \), showing the impact of squaring \( r \) and then scaling it by \(-2\). Finally, \(+1\) is added to adjust the output.
Algebraic expressions like this one are the building blocks for functions and equations in algebra. They give us the framework to model real-world phenomena and solve problems. Understanding how to manipulate and evaluate these expressions is essential for progressing in mathematics.