Chapter 2: Problem 28
Use the point–slope form to write an equation of the line with the given properties or the given graph. Leave the answer in point–slope form. Slope \(-8 ;\) passes through \((3,-2)\)
Short Answer
Expert verified
The equation is \( y + 2 = -8(x - 3) \).
Step by step solution
01
Identify Given Information
We are given the slope \( m = -8 \) and a point on the line \( (x_1, y_1) = (3, -2) \). We need to use this information to write the equation in point–slope form.
02
Understand the Point–Slope Formula
The point–slope form of a line's equation is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is a point on the line.
03
Substitute Values Into the Formula
Insert the given values into the point–slope formula. Replace \( m \) with \(-8\), and \( (x_1, y_1) \) with \((3, -2)\). This gives us: \( y - (-2) = -8(x - 3) \).
04
Simplify the Equation
Simplify the left-side expression \( y - (-2) \) to \( y + 2 \). The equation now becomes \( y + 2 = -8(x - 3) \).
05
Final Equation in Point–Slope Form
The point–slope form equation of the line is \( y + 2 = -8(x - 3) \). This is the final form, and it's already in the required point–slope format.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope
The slope is a fundamental concept when discussing the equation of a line. It is often referred to as the "steepness" or "incline" of the line. Imagine you're skiing down a mountain; the steeper the mountain, the greater the slope. Expressed as a numerical value, the slope of a line gives us an idea of how quickly the line rises or falls as we move from left to right. The slope is represented by the letter \( m \) in mathematical equations. You can think of it as the "rate of change."
- If its value is positive, the line rises as it moves to the right.
- If it's negative, like in our example \( m = -8 \), the line falls as it moves to the right.
- If the slope is zero, the line is perfectly horizontal.
- A vertical line, undefined in slope, is an infinite rise with no run.
Equation of a Line
An equation of a line is a mathematical representation of all the points that lie on that specific line. There are several ways to express the equation of a line, but one of the most useful forms for quickly graphing or finding various line characteristics is the point-slope form.The **point-slope form** is given by the equation \[y - y_1 = m(x - x_1),\]where:- \( m \) is the slope of the line.- \( (x_1, y_1) \) is a specific point through which the line passes.By using the slope and a point on the line, we can easily express all other points on the line. This form highlights the change from a specific point, making it easier to understand and apply to specific problems where you already know a point and the slope. For instance, in our given problem, this equation allows us to directly substitute known values and easily sketch the relationship.
Algebraic Substitution
Algebraic substitution is a technique in which we replace variables in an expression with specific values. In the context of the equation of a line, substitution involves taking the known values, such as a specific point's coordinates and the slope, and inserting them into a formula.To use the point-slope form effectively, we start by identifying the values we need to substitute:- **Slope** \( m = -8 \)- **Point** \((x_1, y_1) = (3, -2)\)The next step is to substitute these values into the point-slope formula:\[y - (-2) = -8(x - 3)\]Upon substitution, it’s crucial to simplify any mathematical expressions, like changing \( y - (-2) \) into \( y + 2 \).By understanding algebraic substitution's role in forming equations, solving problems becomes clearer. It’s a vital skill in algebra that allows you to transform theoretical formulas into practical solutions for real-world applications.