Chapter 11: Problem 59
Use the binomial theorem to expand each expression. See Examples 5 and 6. $$ (c-d)^{5} $$
Short Answer
Expert verified
The expansion is \((c-d)^5 = c^5 - 5c^4d + 10c^3d^2 - 10c^2d^3 + 5cd^4 - d^5\).
Step by step solution
01
Identify the terms
The expression given is \((c-d)^5\). Here, \(a = c\), \(b = -d\), and \(n = 5\). This setup matches the formula \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\).
02
Apply the binomial theorem
Using the binomial theorem, \((c-d)^5 = \sum_{k=0}^{5} \binom{5}{k} c^{5-k} (-d)^k\). We will expand each term by calculating the binomial coefficients and simplifying.
03
Calculate binomial coefficients and terms
For each term in the expansion, calculate \(\binom{5}{k} c^{5-k} (-d)^k\) from \(k = 0\) to \(k = 5\):- \(k = 0\): \(\binom{5}{0} c^5 (-d)^0 = 1 \cdot c^5 \cdot 1 = c^5\)- \(k = 1\): \(\binom{5}{1} c^4 (-d)^1 = 5 \cdot c^4 \cdot (-d) = -5c^4d\)- \(k = 2\): \(\binom{5}{2} c^3 (-d)^2 = 10 \cdot c^3 \cdot d^2 = 10c^3d^2\)- \(k = 3\): \(\binom{5}{3} c^2 (-d)^3 = 10 \cdot c^2 \cdot (-d)^3 = -10c^2d^3\)- \(k = 4\): \(\binom{5}{4} c^1 (-d)^4 = 5 \cdot c \cdot d^4 = 5cd^4\)- \(k = 5\): \(\binom{5}{5} c^0 (-d)^5 = 1 \cdot 1 \cdot (-d)^5 = -d^5\)
04
Write the expanded expression
The expanded expression is a combination of all the individual terms:\[ (c-d)^5 = c^5 - 5c^4d + 10c^3d^2 - 10c^2d^3 + 5cd^4 - d^5 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficients
In algebra, binomial coefficients are incredibly useful when expanding expressions raised to a power using the binomial theorem. The binomial coefficient is typically represented as \( \binom{n}{k} \), pronounced "n choose k". It calculates the number of ways to choose \( k \) elements from a set of \( n \) elements, without regard to the order of selection.
To compute a binomial coefficient, use the formula:
In the expansion of \((c-d)^5\), binomial coefficients were used to determine the coefficients of each term:
To compute a binomial coefficient, use the formula:
- \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
In the expansion of \((c-d)^5\), binomial coefficients were used to determine the coefficients of each term:
- \( \binom{5}{0} = 1 \)
- \( \binom{5}{1} = 5 \)
- \( \binom{5}{2} = 10 \)
- \( \binom{5}{3} = 10 \)
- \( \binom{5}{4} = 5 \)
- \( \binom{5}{5} = 1 \)
Polynomial Expansion
Polynomial expansion involves expressing a power of a binomial (an algebraic expression with two terms) as a polynomial. This is where the binomial theorem comes into play, allowing for quick and systematic expansion.
Using the binomial theorem, the expression \((a+b)^n\) can be expanded into a sum of terms. Each term is constructed from:
Using the binomial theorem, the expression \((a+b)^n\) can be expanded into a sum of terms. Each term is constructed from:
- A binomial coefficient \( \binom{n}{k} \).
- A power of \( a \), specifically \( a^{n-k} \).
- A power of \( b \), specifically \( b^k \).
- The first term is \( c^5 \).
- The second term, due to the negative \( d \), becomes \(-5c^4d\).
- The alternating signs continue as \( 10c^3d^2 \), \(-10c^2d^3 \), and so forth.
Algebraic Expressions
Algebraic expressions are combinations of letters, numbers, and mathematical operators. When working within the framework of binomial expansions, they take a specific form, such as \((c-d)^5\).
Every algebraic expression within the realm of the binomial theorem has:
Every algebraic expression within the realm of the binomial theorem has:
- Variables, like \( c \) and \( d \), representing numbers.
- Coefficients, such as from the binomial coefficients, indicating the number of times a term is counted.
- Operators, like plus or minus signs, defining the relationship between terms.